
Construct the circumcircle and incircle of an equilateral $\Delta ABC$ with side 6cm and center $O$. Find the ratio of radii of circumcircle and incircle.
Answer
621k+ views
Hint: Draw a perpendicular bisector on the equilateral triangle which divides the sides of the equilateral triangle into two equal parts. Take their intersection point to draw a circumcircle and incircle. Now use trigonometric ratios in two different triangles for values of in-radius and circum-radius.
Complete step-by-step answer:
The pictorial representation of the given problem is shown above.
The equilateral triangle ABC with side 6 cm has a circumcircle and an incircle with center O and radii ${r_1}$ and ${r_2}$ respectively.
$ \Rightarrow OB = {r_1}cm,{\text{ }}OD = {r_2}cm$
AE and CD are the perpendicular bisector of BC and AB respectively.
$ \Rightarrow BE = CE = BD = AD = \dfrac{6}{2} = 3cm$
Since, FB is the bisector of $\angle ABC$
$ \Rightarrow \angle FBC = \angle FBA = \dfrac{{{{60}^0}}}{2} = {30^0}$
Because in equilateral triangle all angles are equal which is ${60^0}$
Now, in $\Delta OBE,{\text{ cos3}}{{\text{0}}^0}{\text{ = }}\dfrac{{BE}}{{OB}} = \dfrac{3}{{{r_1}}}$
As we know ${\text{cos3}}{{\text{0}}^0} = \dfrac{{\sqrt 3 }}{2}$
$ \Rightarrow {r_1} = \dfrac{3}{{\cos {{30}^0}}} = \dfrac{3}{{\dfrac{{\sqrt 3 }}{2}}} = \dfrac{6}{{\sqrt 3 }}cm$
Now in $\Delta OBD,{\text{ tan3}}{{\text{0}}^0}{\text{ = }}\dfrac{{OD}}{{BD}} = \dfrac{{{r_2}}}{3}$
As we know ${\text{tan3}}{{\text{0}}^0} = \dfrac{1}{{\sqrt 3 }}$
$ \Rightarrow {r_2} = 3\tan {30^0} = 3\left( {\dfrac{1}{{\sqrt 3 }}} \right) = \sqrt 3 cm$
Now you have to calculate the ratio of radii circumcircle to incircle
$\dfrac{{{r_1}}}{{{r_2}}} = \dfrac{{\dfrac{6}{{\sqrt 3 }}}}{{\sqrt 3 }} = \dfrac{6}{{\sqrt 3 \times \sqrt 3 }} = \dfrac{6}{3} = 2cm$
So, the required ratio of the radii is 2 cm.
Note: In such types of question first draw the pictorial representation of the given problem, then draw the perpendicular bisectors on the triangle which divide its sides into two equal parts, then apply basic trigonometric property and calculate the radii of the two circles, then divide them we will get the required answer.
Complete step-by-step answer:
The pictorial representation of the given problem is shown above.
The equilateral triangle ABC with side 6 cm has a circumcircle and an incircle with center O and radii ${r_1}$ and ${r_2}$ respectively.
$ \Rightarrow OB = {r_1}cm,{\text{ }}OD = {r_2}cm$
AE and CD are the perpendicular bisector of BC and AB respectively.
$ \Rightarrow BE = CE = BD = AD = \dfrac{6}{2} = 3cm$
Since, FB is the bisector of $\angle ABC$
$ \Rightarrow \angle FBC = \angle FBA = \dfrac{{{{60}^0}}}{2} = {30^0}$
Because in equilateral triangle all angles are equal which is ${60^0}$
Now, in $\Delta OBE,{\text{ cos3}}{{\text{0}}^0}{\text{ = }}\dfrac{{BE}}{{OB}} = \dfrac{3}{{{r_1}}}$
As we know ${\text{cos3}}{{\text{0}}^0} = \dfrac{{\sqrt 3 }}{2}$
$ \Rightarrow {r_1} = \dfrac{3}{{\cos {{30}^0}}} = \dfrac{3}{{\dfrac{{\sqrt 3 }}{2}}} = \dfrac{6}{{\sqrt 3 }}cm$
Now in $\Delta OBD,{\text{ tan3}}{{\text{0}}^0}{\text{ = }}\dfrac{{OD}}{{BD}} = \dfrac{{{r_2}}}{3}$
As we know ${\text{tan3}}{{\text{0}}^0} = \dfrac{1}{{\sqrt 3 }}$
$ \Rightarrow {r_2} = 3\tan {30^0} = 3\left( {\dfrac{1}{{\sqrt 3 }}} \right) = \sqrt 3 cm$
Now you have to calculate the ratio of radii circumcircle to incircle
$\dfrac{{{r_1}}}{{{r_2}}} = \dfrac{{\dfrac{6}{{\sqrt 3 }}}}{{\sqrt 3 }} = \dfrac{6}{{\sqrt 3 \times \sqrt 3 }} = \dfrac{6}{3} = 2cm$
So, the required ratio of the radii is 2 cm.
Note: In such types of question first draw the pictorial representation of the given problem, then draw the perpendicular bisectors on the triangle which divide its sides into two equal parts, then apply basic trigonometric property and calculate the radii of the two circles, then divide them we will get the required answer.
Recently Updated Pages
Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

