Question

Complete the following chemical equations.
i) \[{\text{N}}{{\text{H}}_{\text{3}}}{\text{ + 3C}}{{\text{l}}_{\text{2}}} \to…...{\text{ + 3HCl}}\]
ii) \[{\text{N}}{{\text{a}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{3}}}{\text{ + 2HCl}} \to {\text{2NaCl + H2O + ….}}..\]
iii) \[{\text{B}}{{\text{r}}_{\text{2}}}{\text{ + 3}}{{\text{F}}_{\text{2}}} \to….{\text{.}}\]

Answer 1

Hint: We must have to know that in chemistry, equations play a major role. In the reaction three things are main. There are reactants, products and reaction conditions. The reactants are always on the left side of the equation. If more than one reactant in the equation means by using plus sign. The products are always on the right side of the reaction. Something here also follows. More than one product by using plus sign. In between reactant products are used arrows to find the reaction direction in the equation.

Complete answer:
We must have to remember that the balanced chemical equation wise we can predict unknown products in the chemical reaction.
In chemistry, balances the chemical equation means,
We adjust the number moles of reactant and product used to attain an equal number of the same atom in reactant and product in the given chemical reaction.
The given chemical reaction is,
i)\[{\text{N}}{{\text{H}}_{\text{3}}}{\text{ + 3C}}{{\text{l}}_{\text{2}}} \to…...{\text{ + 3HCl}}\]
Ammonia is reacted with excess chlorine to give hydrochloric acid and nitrogentrichloride.
Hence, the chemical equation is
\[{\text{N}}{{\text{H}}_{\text{3}}}{\text{ + 3C}}{{\text{l}}_{\text{2}}} \to {\text{NC}}{{\text{l}}_{\text{3}}}{\text{ + 3HCl}}\]
The given chemical reaction is,
ii) \[{\text{N}}{{\text{a}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{3}}}{\text{ + 2HCl}} \to {\text{2NaCl + H2O + ….}}..\]
The number of sodium, chlorine and hydrogen is balanced in both reactant and product in the above reaction. Remaining sulphur and two oxygen atoms are missing in the product side of the reaction. Hence, the remaining product side is sulphur dioxide.
Hence, the chemical equation is
\[{\text{N}}{{\text{a}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{3}}}{\text{ + 2HCl}} \to {\text{2NaCl + }}{{\text{H}}_{\text{2}}}{\text{O + S}}{{\text{O}}_{\text{2}}}\]
The given chemical reaction is,
iii) \[{\text{B}}{{\text{r}}_{\text{2}}}{\text{ + 3}}{{\text{F}}_{\text{2}}} \to….\]
Bromine is reacted with three moles of fluorine to give bromotrifloride.
Hence, the chemical equation is
\[{\text{B}}{{\text{r}}_{\text{2}}}{\text{ + 3}}{{\text{F}}_{\text{2}}} \to {\text{2Br}}{{\text{F}}_{\text{3}}}\]

Note:
In balanced chemical reaction wise, we predict the side product of the reaction. In some cases we are not able to attain balance by changing the mole. In that case we use the number of countable ions in the product and reactant side of the chemical reaction. In chemistry, redox reaction is one of the types of major reactions. In this redox reaction two methods are used to attain the balanced chemical reaction. There are ion-electron methods and the oxidation number method.