Coefficient of emission of an opaque body is $0.6$. Radiant heat energy is incident on it at the rate of$20watts$. Determine the quantity of radiant heat reflected by it in $2$minutes. A. $480J$ B. $960J$ C. $1920J$ D. $1500J$
Hint: In order to solve this question, we need to find the emissivity of the body given. Emissivity is the measure of degree to be able to radiate energy by a body. Use this concept to find the answer to this question.
Formula used: $E = \varepsilon Pt$where $\varepsilon = $emissivity, $P = $Power, $t = $time taken
Complete answer: Emissivity, $\varepsilon = 1 - 0.6$ $\therefore $because it is an opaque body. $\varepsilon = 0.4$ We have provided $P = $$20watts$, $t = 2$minutes and $\varepsilon = 0.4$ Substituting all these value in below formula we get energy: $ E = \varepsilon Pt \\ E = 0.4 \times 20 \times 2 \times 60 \\ E = 960J \\ $(convert minutes into seconds by multiplying it by $60$)
The radiant heat energy is option(B) $960J$
Note: Points to be kept in mind while solving these questions: Should have proper knowledge of emissivity because emissivity can be confusing sometimes. Should learn all the important formulas as this topic contains lots of formulas which can be messy.