Question

$C{{l}_{2}}+{{H}_{2}}O\to \_\_\_\_\_\_\text{ + }\!\!\_\!\!\text{ }\!\!\_\!\!\text{ }\!\!\_\!\!\text{ }\!\!\_\!\!\text{ }\!\!\_\!\!\text{ }\!\!\_\!\!\text{ }$
(a)-$HCl,\text{ }{{O}_{2}}$
(b)- $HCl,\text{ }HOC{{l}_{2}}$
(c)- $HCl,\text{ }HOCl$
(d)- None of the above.

Answer 1

Hint: Chlorine is the element of group 17 and period 3 of the p-block. When it reacts with water it shows oxidizing property and there is a formation of hydrochloric acid and hypochlorous acid which is very unstable.

Complete step by step answer:
-Chlorine is the element of group 17 and period 3 of the p-block. So it is placed right to the periodic table hence it is a gas specifically saying greenish-yellow gas with a pungent and suffocating odor. It is soluble in water and forms products.
-So the chlorine has oxidizing properties when it is reacted with water because there is an evolution of nascent oxygen.
-So when the chlorine is dissolved in the water there is a formation of chlorine water, but when this chlorine water stands for a long time, the chlorine water will start to lose its yellow color. This is due to the formation of hydrochloric acid whose chemical formula is $HCl$ and hypochlorous acid whose chemical formula is $HOCl$. This formed Hypochlorous acid is a very unstable compound, as soon as it forms it starts to decompose and give nascent oxygen. -This nascent oxygen is responsible for the oxidizing property of chlorine.
The reaction is given below:
$C{{l}_{2}}+{{H}_{2}}O\to HCl+HOCl\to 2HCl+[O]$
-So we can conclude that either in the presence of moisture or the aqueous solution of chlorine is a powerful oxidizing agent.

Therefore, the correct answer is option (c)- $HCl,\text{ }HOCl$.

Note: Some oxidizing properties of chlorine are:
-It can oxidize acidified ferrous to ferric salts, the reaction is given below:
$2FeS{{O}_{4}}+{{H}_{2}}S{{O}_{4}}+C{{l}_{2}}\to F{{e}_{2}}{{(S{{O}_{4}})}_{3}}+2HCl$
-It can oxidize sulfites to sulfates, the reaction is given below:
$N{{a}_{2}}S{{O}_{3}}+C{{l}_{2}}+{{H}_{2}}O\to N{{a}_{2}}S{{O}_{4}}+2HCl$, etc.