Choose the correct statement which describes the position of the point \[\left( -6,2 \right)\] relative to straight lines \[2x+3y-4=0\] and \[6x+9y+8=0\].
a)Below both the lines
b)Above both the lines
c)In between the lines
d)None of these
Answer
636.9k+ views
Hint:Use position of a point with relative to a line and check the condition to solve this problem.
Complete step-by-step answer:
The equations of two lines are \[2x+3y-4=0\] and \[6x+9y+8=0\]. It can be represented as shown below.
A point \[\left( {{x}_{1}},\text{ }{{y}_{1}} \right)\] will lie below the line \[ax+by+c=0\] if \[a{{x}_{1}}+b{{y}_{1}}+c<0\] and vice versa.
We will find the position of the point with respect to first line, i.e., \[2x+3y-4=0\], i.e., substitute \[\left( -6,2 \right)\] in the line equation, we get
\[2(-6)+3(2)-4\]
\[-12+6-4\]
\[-10<0\]
So, the given point \[\left( -6,2 \right)\] is below the line \[2x+3y-4=0\].
Now we will find the position of the point with respect to second line, i.e., \[6x+9y+8=0\], i.e., substitute\[\left( -6,2 \right)\]in the line equation, we get
\[6(-6)+9(2)+8\]
\[-36+18+8\]
\[-10<0\]
So, the given point \[\left( -6,2 \right)\]is below the line \[6x+9y+8=0\].
So, the point \[\left( -6,2 \right)\]is below both the given lines.
Hence the correct answer is option (a).
Note: The possibility of error is that instead of less than it can be considered greater than, i.e., if the \[a{{x}_{1}}+b{{y}_{1}}+c>0\]then the point is below the line. In this case we will get the wrong answer.
Complete step-by-step answer:
The equations of two lines are \[2x+3y-4=0\] and \[6x+9y+8=0\]. It can be represented as shown below.
A point \[\left( {{x}_{1}},\text{ }{{y}_{1}} \right)\] will lie below the line \[ax+by+c=0\] if \[a{{x}_{1}}+b{{y}_{1}}+c<0\] and vice versa.
We will find the position of the point with respect to first line, i.e., \[2x+3y-4=0\], i.e., substitute \[\left( -6,2 \right)\] in the line equation, we get
\[2(-6)+3(2)-4\]
\[-12+6-4\]
\[-10<0\]
So, the given point \[\left( -6,2 \right)\] is below the line \[2x+3y-4=0\].
Now we will find the position of the point with respect to second line, i.e., \[6x+9y+8=0\], i.e., substitute\[\left( -6,2 \right)\]in the line equation, we get
\[6(-6)+9(2)+8\]
\[-36+18+8\]
\[-10<0\]
So, the given point \[\left( -6,2 \right)\]is below the line \[6x+9y+8=0\].
So, the point \[\left( -6,2 \right)\]is below both the given lines.
Hence the correct answer is option (a).
Note: The possibility of error is that instead of less than it can be considered greater than, i.e., if the \[a{{x}_{1}}+b{{y}_{1}}+c>0\]then the point is below the line. In this case we will get the wrong answer.
Recently Updated Pages
Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Chemistry: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

State and prove Bernoullis theorem class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

Discuss the various forms of bacteria class 11 biology CBSE

