Question

How do you calculate the percentage by Mass of carbon in carbon monoxide?

Answer 1

Hint: Mass of a carbon atom is the mass of protons and neutrons present in that atom and mass of a neutron or proton is $1$$amu$ . The mass of the electron is neglected because the mass of the electron is negligible in comparison with the proton.

Complete step-by-step answer:
To calculate the mass percent of an element in a compound, we divide the mass of the element in 1 mole of the compound by the compound's molar mass and multiply the result by 100.
As the mass of a carbon atom is $12$ $amu$ .
And atomic mass of oxygen is $16$ $amu$.
The mass of compound carbon monoxide will be $28$ $amu$.
Now we will calculate the mass percentage of carbon in carbon monoxide.
So the formula for mass percentage = (mass of element in 1 mole of compound /mass of compound ) x 100
Lets calculate this
$\dfrac{{12}}{{28}} \times 100$ $ = $ $4.2$

So the mass percentage of carbon in carbon monoxide is 4.2 percent.

Note: Molar mass is the mass of a given substance divided by the amount of that substance divided by the amount of that substance, measured in $g/mol$. For example, the atomic mass of the titanium is 47.88 $amu$ or 47.88 $g/mol$ . In the 47.88 grams of titanium, there is one mole, or $6.022 \times {10^{23}}$ titanium ions