Question

Calculate the mass of sodium acetate (${\text{C}}{{\text{H}}_{\text{3}}}{\text{COONa}}$) require to make 500 mL of 0.375 M solution:
a.) 10.45 g
b.) 12.36 g
c.) 15.88 g
d.) 15.38 g

Answer 1

Hint: We need to find the molar mass of sodium acetate at first. Molar mass of a given chemical compound is the mass of the compound divided by the amount of substance, expressed in moles.

Complete step-by-step answer:
0.375 M solution of ${\text{C}}{{\text{H}}_{\text{3}}}{\text{COONa = 0}}{\text{.375 moles}}$ of ${\text{C}}{{\text{H}}_{\text{3}}}{\text{COONa}}$ per 1000ml
Number of moles of ${\text{C}}{{\text{H}}_{\text{3}}}{\text{COONa in 500 ml = }}\dfrac{{{\text{0}}{\text{.375}}}}{{{\text{100}}}}\text{x}{\text{ 500 = 0}}{\text{.1875 moles}}$ ${\text{C}}{{\text{H}}_{\text{3}}}{\text{COONa in 500 ml = }}\dfrac{{{\text{0}}{\text{.375}}}}{{{\text{100}}}}\text{x}{\text{ 500 = 0}}{\text{.1875 moles}}$
Molar mass of sodium acetate ${\text{ = 82}}{\text{. 0245 g/mole}}$
Therefore, mass of ${\text{C}}{{\text{H}}_{\text{3}}}{\text{COONa}}$ required $= {\text{ }}82.{\text{ }}0245{\text{ }} \times {\text{ }}0.1875{\text{ }} = {\text{ }}15.38{\text{ }}g$
So the correct option is Option D.

Additional Information:
Mole is defined as the measurement for the amount of substance in the International System of Units.
Talking about acetic acid, it is a colourless liquid organic compound. When it is diluted, it is also known as glacial acetic acid. In acetic acid, there is the presence of vinegar about 4 to 5 percent.
The molar mass is an average of many instances of the compound, which often vary in mass due to the presence of isotopes. The molar mass is an intensive property, and it does not depend on the size of the sample. The basic unit of molar mass is expressed in kg per mole.

Note: The molar mass of a given compound can be calculated by adding the standard atomic masses of the constituent atoms. The atomic masses are expressed in grams per mole.