
How do you calculate the concentration of solute?
Answer
536.4k+ views
Hint: Concentration is defined as ratio of amount of solute to amount of solution [It is a homogeneous mixture containing solute and solvent, where the solvent is major component of solution and solute is minor component and active ingredient.] Solute is minor forms like gas, liquid or solid.
Complete step by step answer:
There are many ways of expressing concentration:
Parts per million (PPm)
Percentage by weight (%W/W)
Percentage by volume. (%V/V)
Molality $(\text{m})$
Molarity $(\text{M})$
The most commonly used and accurate method to find concentration is ‘’Molarity’’ and ‘’Molality’’
Molality $(\text{m})$: It is a measure of number of moles of solute present in 1 kg of solvent.
$\text{m}=\dfrac{\text{moles of solvent}}{\text{mass of solution}}=\dfrac{\text{n (moles)}}{\text{kg}}$
Molarity/Mole concentration: It is defined as the number of moles dissolved in 1L solution.
$\text{M=}\dfrac{\text{moles solutes}}{\text{volume of solution}}=\dfrac{\text{n (moles)}}{\text{v}\,\text{(L)}}$
Unit $=\text{M,}\ \text{mol/L}$
Mole: It is a unit which is used to quantitatively measures the amount of substance
$1\ \text{mole}=6.022\times {{10}^{23}}$ particles or molecules of substance
$6.022\times {{10}^{23}}=$ Avogadro number
Mole of any substance is calculated by dividing the mass of that substance by the molar mass (MM) of that molecule or atom in gm.
Example: A $20.0\ \text{mL}$ of water contain 10.5 gram of glucose $(\text{MM}=\text{180}\text{.18}\ \text{g/mol}).$ The molarity of solution will be:
Convert g of glucose to mol of glucose
$10.5\ \text{g glucose}\times \dfrac{\text{1 mol glucose}}{\text{180}\text{.18 g glucose}}=0.0583\ \text{mol}$
Convert ml to L
$\text{20}\text{.0 mL}\times \dfrac{\text{0}\text{.001}\ \text{L}}{1\,\text{mL}}=0.0200\ \text{L}$
Molarity $=\dfrac{\text{0}\text{.0583 mol glucose}}{0.0200\ \text{L}}=2.92\ \text{M}$
Note: Colligative properties are properties of solutions that are affected by the number of particles. E.g: Boiling point elevation, Freezing point depression and osmotic pressure.
Colligative properties depend on concentration of solute but not depend upon the identity of solute.
Complete step by step answer:
There are many ways of expressing concentration:
Parts per million (PPm)
Percentage by weight (%W/W)
Percentage by volume. (%V/V)
Molality $(\text{m})$
Molarity $(\text{M})$
The most commonly used and accurate method to find concentration is ‘’Molarity’’ and ‘’Molality’’
Molality $(\text{m})$: It is a measure of number of moles of solute present in 1 kg of solvent.
$\text{m}=\dfrac{\text{moles of solvent}}{\text{mass of solution}}=\dfrac{\text{n (moles)}}{\text{kg}}$
Molarity/Mole concentration: It is defined as the number of moles dissolved in 1L solution.
$\text{M=}\dfrac{\text{moles solutes}}{\text{volume of solution}}=\dfrac{\text{n (moles)}}{\text{v}\,\text{(L)}}$
Unit $=\text{M,}\ \text{mol/L}$
Mole: It is a unit which is used to quantitatively measures the amount of substance
$1\ \text{mole}=6.022\times {{10}^{23}}$ particles or molecules of substance
$6.022\times {{10}^{23}}=$ Avogadro number
Mole of any substance is calculated by dividing the mass of that substance by the molar mass (MM) of that molecule or atom in gm.
Example: A $20.0\ \text{mL}$ of water contain 10.5 gram of glucose $(\text{MM}=\text{180}\text{.18}\ \text{g/mol}).$ The molarity of solution will be:
Convert g of glucose to mol of glucose
$10.5\ \text{g glucose}\times \dfrac{\text{1 mol glucose}}{\text{180}\text{.18 g glucose}}=0.0583\ \text{mol}$
Convert ml to L
$\text{20}\text{.0 mL}\times \dfrac{\text{0}\text{.001}\ \text{L}}{1\,\text{mL}}=0.0200\ \text{L}$
Molarity $=\dfrac{\text{0}\text{.0583 mol glucose}}{0.0200\ \text{L}}=2.92\ \text{M}$
Note: Colligative properties are properties of solutions that are affected by the number of particles. E.g: Boiling point elevation, Freezing point depression and osmotic pressure.
Colligative properties depend on concentration of solute but not depend upon the identity of solute.
Recently Updated Pages
A man running at a speed 5 ms is viewed in the side class 12 physics CBSE

State and explain Hardy Weinbergs Principle class 12 biology CBSE

Which of the following statements is wrong a Amnion class 12 biology CBSE

Two Planoconcave lenses 1 and 2 of glass of refractive class 12 physics CBSE

The compound 2 methyl 2 butene on reaction with NaIO4 class 12 chemistry CBSE

Bacterial cell wall is made up of A Cellulose B Hemicellulose class 12 biology CBSE

Trending doubts
What are the major means of transport Explain each class 12 social science CBSE

Which are the Top 10 Largest Countries of the World?

Draw a labelled sketch of the human eye class 12 physics CBSE

Explain sex determination in humans with line diag class 12 biology CBSE

The pH of the pancreatic juice is A 64 B 86 C 120 D class 12 biology CBSE

Give 10 examples of unisexual and bisexual flowers

