By what acceleration, the wedge should move so that the block moves upwards along the surface of the wedge with an acceleration of $g\sin \theta $.
A. $2g\cos \theta $
B. $g\sin \theta $
C. $2g\tan \theta $
D. $g\cos \theta $
Answer
588.3k+ views
Hint:To construct a free-body diagram, we draw the point of concern, all forces acting on it, and resolve all force vectors into x– and y–components. A separate free-body diagram is required for each object in the question.
Complete step by step answer:
After drawing a free body diagram, we will get the following figure,
In the following question, we observe with respect to wedge. Hence, we apply pseudo force on the block. After substituting the values from free body diagram we will get,
$ma\cos \theta - mg\sin \theta = ma' \\
\Rightarrow ma\cos \theta - mg\sin \theta = mg\sin \theta \\
\Rightarrow a\cos \theta = 2g\sin \theta \\
\Rightarrow a = \dfrac{{2g\sin \theta }}{{\cos \theta }} \\
\therefore a = 2g\tan \theta \\ $
Hence, the correct option is C.
Note:Four forces are not often applied to objects. In certain cases, the number of forces described by a free-body diagram may be one, two, or three. In a free-body diagram, the number of forces that must be drawn is not a hard and fast rule. There is only one guideline to drawing free-body diagrams: reflect all of the forces that exist with that object in the given situation.
Complete step by step answer:
After drawing a free body diagram, we will get the following figure,
In the following question, we observe with respect to wedge. Hence, we apply pseudo force on the block. After substituting the values from free body diagram we will get,
$ma\cos \theta - mg\sin \theta = ma' \\
\Rightarrow ma\cos \theta - mg\sin \theta = mg\sin \theta \\
\Rightarrow a\cos \theta = 2g\sin \theta \\
\Rightarrow a = \dfrac{{2g\sin \theta }}{{\cos \theta }} \\
\therefore a = 2g\tan \theta \\ $
Hence, the correct option is C.
Note:Four forces are not often applied to objects. In certain cases, the number of forces described by a free-body diagram may be one, two, or three. In a free-body diagram, the number of forces that must be drawn is not a hard and fast rule. There is only one guideline to drawing free-body diagrams: reflect all of the forces that exist with that object in the given situation.
Recently Updated Pages
If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

A car covers the first half distance between two places class 11 physics CBSE

The resultant of two vectors overrightarrow P and overrightarrow class 11 physics CBSE

Find the value of cos 135 class 11 maths CBSE

A mass M is held in place by an applied force F and class 11 physics CBSE

A solution of glucose in water is labelled as 10 dfracwv class 11 chemistry CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Find the value of the expression given below sin 30circ class 11 maths CBSE

What do you mean by retardation What is its SI uni class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Difference between physical and chemical change class 11 chemistry CBSE

