Question

# Boric acid is an acidic molecule because its molecule;A] accepts $OH^-$ from water releasing protonB] combines with proton from water moleculeC] contains replaceable $H^+$ ion D] gives up proton

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Hint: Boron belongs to p-block and is the first member of its group. Boric acid has a formula of $B[OH]_3$. It is also known as orthoboric acid. It is monobasic Lewis acid. Oxygen gives one electron to boron, so it acquires a positive charge and becomes unstable, so it furnishes $1H^+$ and gets stable.

A] As boron is small in size and boron has 5 electrons in its valence shell. It accepts $OH^-$ from the water molecule and loses its proton.
$B\mathop {\left( {OH} \right)}\nolimits_3 + \mathop H\nolimits_2 O \to \left\{ {B\mathop {\left[ {OH} \right]}\nolimits_4 } \right\} + \mathop H\nolimits^ +$
Our required Ans is ‘A’ that is accepts $OH^-$ ion from water and gives proton.