Courses
Courses for Kids
Free study material
Offline Centres
More
Store Icon
Store

What is the bond order of \[N-N\] bond in \[{{N}_{2}}O\] ?
A.1
B.1.5
C.2
D.2.5

seo-qna
Last updated date: 23rd Jul 2024
Total views: 349.8k
Views today: 5.49k
Answer
VerifiedVerified
349.8k+ views
Hint: We know that the difference between the number of bonds and antibonds is known as bond order. The bond number is the total number of electron pairs (bonds) that exist between two atoms. A bond's stability is determined by its bond number. The bond number of isoelectronic organisms is the same.

Complete answer:
Bond order is characterized as half the difference between the number of bonding electrons and the number of antibonding electrons in molecular orbital theory. For bonds near their equilibrium lengths, this often but not always produces similar results, but it does not work for extended bonds. Bond order is often used extensively in valence bond theory as a measure of bond power. The Bond order for the given molecule is given by: (Total number of electron pairs in \[N-O\] bonds) / (total number of \[N-O\]bonds) the number of \[A-O\] bonds is three, and the number of resonating structures is two
\[Bond\text{ }order\text{ }will\text{ }be\text{ }\dfrac{Total\text{ }no.\text{ }of\text{ }bonds}{Total\text{ }no.\text{ }of\text{ }canonical\text{ }structures}\text{=}\dfrac{5}{2}\text{=}2.5.\]
The third structure is not possible as nitrogen cannot have two negative charges so we will consider only two structures. In first structure there are three bonds between both nitrogen and in second structure there are two bonds so total bonds is \[5.\]
\[:N\equiv \overset{+1}{\mathop{\overset{{}}{\mathop{N}}\,}}\,-\overset{-1}{\mathop{\underset{\centerdot \centerdot }{\overset{\centerdot \centerdot }{\mathop{O}}}\,}}\,:~~~~~~\overset{-1}{\mathop{\underset{\centerdot \centerdot }{\overset{\centerdot \centerdot }{\mathop{N}}}\,}}\,=\overset{+1}{\mathop{\overset{{}}{\mathop{N}}\,}}\,=\overset{{}}{\mathop{\underset{\centerdot \centerdot }{\overset{\centerdot \centerdot }{\mathop{O}}}\,}}\,~~~~~~:\overset{-2}{\mathop{\underset{\centerdot \centerdot }{\overset{\centerdot \centerdot }{\mathop{N}}}\,}}\,-\overset{+1}{\mathop{\overset{{}}{\mathop{N}}\,}}\,\equiv \overset{-1}{\mathop{\underset{{}}{\overset{{}}{\mathop{O}}}\,}}\,:\]
Therefore, the correct answer is option D.

Note:
The bond order expresses the bond's safety. The molecular orbital makes the idea of a chemical bond's bond order simple to comprehend. It measures the strength of atom-to-atom covalent bonds. The nitrogen ion is a type of ion that is found in nature. The cation \[NO_{2}^{+}\] (removal of electrons is known as cation). It's made by removing an electron from a molecule of nitrogen dioxide.