Answer
Verified
384k+ views
Hint:While balancing a chemical equation we have to keep in mind that the number of atoms on each side should be equal. We can multiply the stoichiometric coefficient of each reactant and product and make each type of atom the same. Here, we have an organic compound which is propane is doing combustion in presence of oxygen and gives carbon dioxide and water.
Complete step-by-step answer:We have propane which reacts with oxygen and performs a combustion reaction. The products of combustion reaction are carbon dioxide and water. So let’s start with counting the number of atoms left hand side and right hand side. We have equation as,
$C{H_3}C{H_2}C{H_3}\,(g)\, + \,{O_2}(g)\, \to \,C{O_2}\,(g)\, + \,{H_2}O(l)\, - - - - - - - - - - - - - - (1)$
Here atoms on the left hand side are, $(3C,\,8H\,and\,2O)$ and atoms on the right hand side are $(1C,\,2H\,and\,3O)$ . So as we see that number of atoms are less on right hand side so let’s multiply the carbon dioxide molecule by $3$ after that we get the equation as,
$C{H_3}C{H_2}C{H_3}\,(g)\, + \,{O_2}(g)\, \to \,3C{O_2}\,(g)\, + \,{H_2}O(l)\, - - - - - - - - - - - - - - (2)$
Now as we see that carbon get balanced having three carbons on both side, now we have to balanced hydrogens and oxygens by multiplying the water molecule by number $4$ and oxygen on left hand side by number $5$ .
$C{H_3}C{H_2}C{H_3}\,(g)\, + \,5{O_2}(g)\, \to \,3C{O_2}\,(g)\, + \,4{H_2}O(l)\, - - - - - - - - - - - - - - (3)$
The above equation is completely balanced, there are three carbon on both sides with $10\,oxygen$ on both sides. Also we have hydrogens as $8\,hydrogens$ . Thus complete balanced equation of combustion reaction between propane and oxygen is:
$C{H_3}C{H_2}C{H_3}\,(g)\, + \,5{O_2}(g)\, \to \,3C{O_2}\,(g)\, + \,4{H_2}O(l)$
Note:As we see that the number of atoms on both sides becomes equal. The same mechanism takes place when we have to balance the other hydrocarbons. We have two categories of hydrocarbons, saturated and unsaturated. In unsaturated one we have double or triple bonds while in saturated hydrocarbons only a single bond is present. Mainly we have to balance the carbons, hydrogens and oxygens in these types of reactions.
Complete step-by-step answer:We have propane which reacts with oxygen and performs a combustion reaction. The products of combustion reaction are carbon dioxide and water. So let’s start with counting the number of atoms left hand side and right hand side. We have equation as,
$C{H_3}C{H_2}C{H_3}\,(g)\, + \,{O_2}(g)\, \to \,C{O_2}\,(g)\, + \,{H_2}O(l)\, - - - - - - - - - - - - - - (1)$
Here atoms on the left hand side are, $(3C,\,8H\,and\,2O)$ and atoms on the right hand side are $(1C,\,2H\,and\,3O)$ . So as we see that number of atoms are less on right hand side so let’s multiply the carbon dioxide molecule by $3$ after that we get the equation as,
$C{H_3}C{H_2}C{H_3}\,(g)\, + \,{O_2}(g)\, \to \,3C{O_2}\,(g)\, + \,{H_2}O(l)\, - - - - - - - - - - - - - - (2)$
Now as we see that carbon get balanced having three carbons on both side, now we have to balanced hydrogens and oxygens by multiplying the water molecule by number $4$ and oxygen on left hand side by number $5$ .
$C{H_3}C{H_2}C{H_3}\,(g)\, + \,5{O_2}(g)\, \to \,3C{O_2}\,(g)\, + \,4{H_2}O(l)\, - - - - - - - - - - - - - - (3)$
The above equation is completely balanced, there are three carbon on both sides with $10\,oxygen$ on both sides. Also we have hydrogens as $8\,hydrogens$ . Thus complete balanced equation of combustion reaction between propane and oxygen is:
$C{H_3}C{H_2}C{H_3}\,(g)\, + \,5{O_2}(g)\, \to \,3C{O_2}\,(g)\, + \,4{H_2}O(l)$
Note:As we see that the number of atoms on both sides becomes equal. The same mechanism takes place when we have to balance the other hydrocarbons. We have two categories of hydrocarbons, saturated and unsaturated. In unsaturated one we have double or triple bonds while in saturated hydrocarbons only a single bond is present. Mainly we have to balance the carbons, hydrogens and oxygens in these types of reactions.
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
Why Are Noble Gases NonReactive class 11 chemistry CBSE
Let X and Y be the sets of all positive divisors of class 11 maths CBSE
Let x and y be 2 real numbers which satisfy the equations class 11 maths CBSE
Let x 4log 2sqrt 9k 1 + 7 and y dfrac132log 2sqrt5 class 11 maths CBSE
Let x22ax+b20 and x22bx+a20 be two equations Then the class 11 maths CBSE
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
At which age domestication of animals started A Neolithic class 11 social science CBSE
Which are the Top 10 Largest Countries of the World?
Give 10 examples for herbs , shrubs , climbers , creepers
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Difference Between Plant Cell and Animal Cell
Write a letter to the principal requesting him to grant class 10 english CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Fill in the blanks A 1 lakh ten thousand B 1 million class 9 maths CBSE