Question

Balance the following chemical equations.
A.\[HN{O_3} + Ca{\left( {OH} \right)_2} \to Ca{\left( {N{O_3}} \right)_2} + {H_2}O\]
B.\[NaOH + {H_2}S{O_4} \to N{a_2}S{O_4} + {H_2}O\]
C.\[NaCl + AgN{O_3} \to AgCl + NaN{O_3}\]
D.\[BaC{l_2} + {H_2}S{O_4} \to BaS{O_4} + HCl\]

Answer 1

Hint: To balance the chemical reaction, first consider the unbalanced equation to show the reactants and products. Then Identify and count the atoms in both the reactants and products in the following reaction. Then to make the number of atoms the same on both the reactants and products sides, we need to add coefficients (the numbers in front of the formulas) so that the number of atoms of each element is the same on both sides of the chemical equation.

Complete answer:
The law of conservation of matter states that matter cannot be produced or destroyed in a closed system. So, chemical equations must be balanced, to satisfy the law of conservation of matter. Balanced chemical equations have the same number and type of each atom on both sides of the equation.
(a)
Given unbalanced chemical equation is
\[HN{O_3} + Ca{\left( {OH} \right)_2} \to Ca{\left( {N{O_3}} \right)_2} + {H_2}O\]--(1)
In the equation (1), the number of \[H\]atoms in the reactants and products are \[3\]and \[2\] respectively. So, multiple \[HN{O_3}\]( Nitric acid) and \[{H_2}O\] by \[2\]. Then the number of atoms in the reactants and products become the same.
Then the balanced chemical equation is
\[2HN{O_3} + Ca{\left( {OH} \right)_2} \to Ca{\left( {N{O_3}} \right)_2} + 2{H_2}O\]
(b)
Given unbalanced chemical equation is
\[NaOH + {H_2}S{O_4} \to N{a_2}S{O_4} + {H_2}O\]--(2)
In the equation (2), the number of \[H\]atoms in the reactants and products are \[3\]and \[2\] respectively. So, multiple \[NaOH\](Sodium hydroxide) and \[{H_2}O\] by \[2\]. Then the number of atoms in the reactants and products become the same.
Then the balanced chemical equation is
\[2NaOH + {H_2}S{O_4} \to N{a_2}S{O_4} + 2{H_2}O\]

(c)
Given chemical equation is
\[NaCl + AgN{O_3} \to AgCl + NaN{O_3}\]--(3)
In the equation (3), the number of atoms in the reactants and products are the same. Hence the given chemical equation is balanced.

(d)
Given unbalanced chemical equation is
\[BaC{l_2} + {H_2}S{O_4} \to BaS{O_4} + HCl\]--(4)
In the equation (4), the number of \[H\]atoms in the reactants and products are \[2\]and \[1\] respectively. So, multiple \[HCl\] (Hydrochloric acid) by \[2\]. Then the number of atoms in the reactants and products become the same.
Then the balanced chemical equation is
\[BaC{l_2} + {H_2}S{O_4} \to BaS{O_4} + 2HCl\].

Note:
Note that the coefficients in a balanced equation must be the simplest whole number ratio. Representation of a chemical reaction in terms of symbols and chemical formula of the reactants and products taking part in the reaction is known as a chemical equation. The five basic types of chemical reactions are combination, decomposition, single-replacement, double-replacement, and combustion.