
Balance the equation $ N{a_2}C{O_3} + HCl \to NaCl + C{O_2} + {H_2}O $ .
Answer
498.3k+ views
Hint: A chemical equation in which number of atoms of all the elements are equal on both reactants and products side is known as balanced chemical reaction and if the number of atoms of all the elements on both sides (products and reactants) are not equal then the reaction is known as unbalanced chemical reaction.
Complete answer:
So, we know that, in a chemical equation, if the number of atoms of all the elements are equal on both reactants and products side it is a balanced chemical equation otherwise it is an unbalanced chemical equation.
We need to balance an unbalanced chemical equation in order to follow the “law of conservation of mass” which states that mass can neither be created nor be destroyed.
Now, if we look at given chemical equation:
$ N{a_2}C{O_3} + HCl \to NaCl + C{O_2} + {H_2}O $
First, we will make a table and count the number of atoms of each element on both reactant and product sides.
Here, we can see that sodium and hydrogen atoms are not balanced.
First, we will balance the sodium atoms by multiplying $ NaCl $ in the product side with $ 2 $ .
Hence, the equation becomes:-
$ N{a_2}C{O_3} + HCl \to 2NaCl + C{O_2} + {H_2}O $
Now, hydrogen and chlorine are unbalanced. So, to balance them, we will multiply $ HCl $ in reactions with 2.
$ N{a_2}C{O_3} + 2HCl \to 2NaCl + C{O_2} + {H_2}O $
Hence, now all the atoms in reactant and product sides are equal so the balanced chemical equation is:
$ N{a_2}C{O_3} + 2HCl \to 2NaCl + C{O_2} + {H_2}O $
Note:
While balancing any element or equation, remember it should be multiplied a number as we have done in the above case. Never try balancing an equation by changing the subscripts otherwise the molecular formula of the compound will change and it will not be the same as the compound given in the equation.
Complete answer:
So, we know that, in a chemical equation, if the number of atoms of all the elements are equal on both reactants and products side it is a balanced chemical equation otherwise it is an unbalanced chemical equation.
We need to balance an unbalanced chemical equation in order to follow the “law of conservation of mass” which states that mass can neither be created nor be destroyed.
Now, if we look at given chemical equation:
$ N{a_2}C{O_3} + HCl \to NaCl + C{O_2} + {H_2}O $
First, we will make a table and count the number of atoms of each element on both reactant and product sides.
| Element | Reactant side | Product side |
| Sodium, Na | $ 2 $ | $ 1 $ |
| Carbon, C | $ 1 $ | $ 1 $ |
| Oxygen, O | $ 3 $ | $ 3 $ |
| Hydrogen, H | $ 1 $ | $ 2 $ |
| Chlorine, Cl | $ 1 $ | $ 1 $ |
Here, we can see that sodium and hydrogen atoms are not balanced.
First, we will balance the sodium atoms by multiplying $ NaCl $ in the product side with $ 2 $ .
Hence, the equation becomes:-
$ N{a_2}C{O_3} + HCl \to 2NaCl + C{O_2} + {H_2}O $
| Element | Reactant side | Product side |
| Sodium, Na | $ 2 $ | $ 2 $ |
| Carbon, C | $ 1 $ | $ 1 $ |
| Oxygen, O | $ 3 $ | $ 3 $ |
| Hydrogen, H | $ 1 $ | $ 2 $ |
| Chlorine, Cl | $ 1 $ | $ 2 $ |
Now, hydrogen and chlorine are unbalanced. So, to balance them, we will multiply $ HCl $ in reactions with 2.
$ N{a_2}C{O_3} + 2HCl \to 2NaCl + C{O_2} + {H_2}O $
| Element | Reactant side | Product side |
| Sodium, Na | $ 2 $ | $ 2 $ |
| Carbon, C | $ 1 $ | $ 1 $ |
| Oxygen, O | $ 3 $ | $ 3 $ |
| Hydrogen, H | $ 2 $ | $ 2 $ |
| Chlorine, Cl | $ 2 $ | $ 2 $ |
Hence, now all the atoms in reactant and product sides are equal so the balanced chemical equation is:
$ N{a_2}C{O_3} + 2HCl \to 2NaCl + C{O_2} + {H_2}O $
Note:
While balancing any element or equation, remember it should be multiplied a number as we have done in the above case. Never try balancing an equation by changing the subscripts otherwise the molecular formula of the compound will change and it will not be the same as the compound given in the equation.
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
Differentiate between an exothermic and an endothermic class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

State the laws of reflection of light

