Courses
Courses for Kids
Free study material
Offline Centres
More
Store Icon
Store
seo-qna
SearchIcon
banner

Average voltage for the given source is
seo images

A) V0
B) 2V0
C) V02
D) 3V02

Answer
VerifiedVerified
503.7k+ views
like imagedislike image
Hint: The average voltage of a periodic waveform like this triangular one can be defined as the quotient of the area under the waveform with respect to time. To calculate you need to average out all the instantaneous values along the time axis with time being one full period which for such a continuous waveform is calculated by calculating the area under the curve.

Formula used:
If a triangle has a base b and height h, then the area of the triangle can be expressed as
Δ=12(b×h) ……………(1)

Complete step by step answer:
Given:
The peak of the voltage from the triangular waveforms shown in the graph is 2V0.
The period of the waveform from the graph is T.
To get: The average voltage Vavg for the given source.

Step 1:
You can calculate the area under each periodic triangle from eq (1).
You can see for each triangle the base is T2 and the height is 2V0.
So, the area under each triangle is
Δ=12×(base×height)
=12×(T2×2V0)
=V0T2 ……..(2)

Step 2:
So, the quotient of the area under the waveform with respect to time period T is the area you found just now.
Calculate the average voltage Vavg from the definition
Vavg=ΔT
where Δ is the quotient of the area under the waveform with respect to time, T is the period of the waveform.
Vavg=V0T2T
=V02

The average voltage for the given source is V02. Hence, option (C) is correct.

Note:
Here you can approach to calculate the area under the curve through any method, but for the continuous waveform, you need to use this approach for the appropriate solution. One needs to be very careful in choosing the period. The symmetry of the wave form should be noticed for this type of regular waveform which can be easily computed.