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**Hint:**Avogadro's Number speaks to the complete number of particles or atoms present in one mole of any substance. It is a steady worth and is utilized in computing the quantity of rudimentary particles present in a given example of any substance. The estimation of Avogadro's Number is \[6.023 \times {10^{23}}\] particles or atoms per mole.

**Complete step by step answer:**

The thought here is that you need to utilize neon's molar mass, which mentions to you what the mass of one mole of the component is, to decide the number of moles you have in that \[5.9 - g\] test.

When you know the number of moles you have, you can utilize Avogadro's number to locate the quantity of molecules.

Thus, neon has a molar mass of \[20.18{\text{ }}g/mol\] , which implies that each mole of neon has a mass of \[20.18{\text{ }}g\] .

Your example of neon will along these lines contain

$5.9{{\text{g}}} \cdot \dfrac{{{\text{1 mole Ne}}}}{{20.18{{\text{g}}}}} = {\text{0}}{\text{.2924 moles Ne}}$

Presently, you realize that one mole of any component contains precisely \[6.022 \cdot {10^{23}}\] particles of that component - this is Avogadro's number.

All things considered, on the off chance that one mole contains that numerous particles, it follows that you test will contain

\[0.2924{{{\text{moles Ne}}}} \cdot \dfrac{{6.022 \cdot {{10}^{23}}{\text{atoms of Ne}}}}{{1{{{\text{mole Ne}}}}}} = \left[ {1.8 \cdot {{10}^{23}}{\text{atoms}}} \right]{\text{ of Ne}}\]

The appropriate response is adjusted to two sig figs, the quantity of sig figs you have for the mass of the example

**Note:**Molality and molarity are two unique ideas. Molality is fundamentally the proportion of the quantity of moles of the substance to the absolute volume of the arrangement. Then again, molality is spoken to as the proportion of the quantity of moles of the substance to the complete mass of the dissolvable. Both these amounts are incredibly valuable while addressing questions identified with substance focuses.

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