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# How many atoms of neon are in $5.9$ grams of neon?

Last updated date: 22nd Feb 2024
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Hint: Avogadro's Number speaks to the complete number of particles or atoms present in one mole of any substance. It is a steady worth and is utilized in computing the quantity of rudimentary particles present in a given example of any substance. The estimation of Avogadro's Number is $6.023 \times {10^{23}}$ particles or atoms per mole.

The thought here is that you need to utilize neon's molar mass, which mentions to you what the mass of one mole of the component is, to decide the number of moles you have in that $5.9 - g$ test.
Thus, neon has a molar mass of $20.18{\text{ }}g/mol$ , which implies that each mole of neon has a mass of $20.18{\text{ }}g$ .
$5.9{{\text{g}}} \cdot \dfrac{{{\text{1 mole Ne}}}}{{20.18{{\text{g}}}}} = {\text{0}}{\text{.2924 moles Ne}}$
Presently, you realize that one mole of any component contains precisely $6.022 \cdot {10^{23}}$ particles of that component - this is Avogadro's number.
$0.2924{{{\text{moles Ne}}}} \cdot \dfrac{{6.022 \cdot {{10}^{23}}{\text{atoms of Ne}}}}{{1{{{\text{mole Ne}}}}}} = \left[ {1.8 \cdot {{10}^{23}}{\text{atoms}}} \right]{\text{ of Ne}}$