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# AssertionThe value of Boyle’s temperature for a real gas is $\left( {{{\text{T}}_{\text{B}}}\,{\text{ = }}\,\dfrac{{\text{a}}}{{{\text{Rb}}}}} \right)$ReasonAt Boyle’s temperature, ${{\text{T}}_{\text{B}}}$, real gases behave ideally over a long range of pressure.(A) Both Assertion and Reason are correct and Reason is the correct explanation for Assertion.(B) Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion(C) Assertion is correct but Reason is incorrect.(D) Assertion is incorrect but Reason is correct.

Last updated date: 22nd Jul 2024
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Hint: The temperature at which the second virial coefficient, ${{\text{B}}_{\text{2}}}\left( {\text{T}} \right)$, becomes zero is known as the Boyle temperature. At this temperature, the attractive and repulsive forces acting on the gas particles balance each other out.

Boyle temperature, also known as Boyle poin, is the temperature at which a natural gas acts as an ideal gas over a large range of pressures ($100$ atm).
$\left( {{{\text{T}}_{\text{B}}}\,{\text{ = }}\,\dfrac{{\text{a}}}{{{\text{Rb}}}}} \right)$ is the Boyle Temperature for real gas.