Answer
Verified
329.6k+ views
Hint: Make use of the property that says that the centre of a conic bisects every chord that passes through the centre of a conic section.
First, let’s find the centre of this conic section. To find this, let’s first see if the equation changes when we replace $x$ with $y$ and vice versa. If the equation remains unchanged, then that means that the centre of the conic is the origin itself.
Let’s exchange $x$ and $y$ in the equation now. Doing so, we get :
${{y}^{2}}+{{x}^{2}}+yx=1$ which is the same as the original question.
Hence, we know that the centre of this conic is in fact the origin.
It is a property of all conics that every chord drawn in the conic that passes through its centre is bisected by the centre of that conic. Applying this property to this question, since we don’t have one particular chord, and it’s any chord passing through the origin, we can say that $(p,q)$ is actually the centre of this conic. Hence, this point should be equal to the origin since that is the centre of this conic.
$\begin{align}
& (p,q)=(0,0) \\
& \Rightarrow p=0,q=0 \\
& \Rightarrow p+q+12=0+0+12=12 \\
\end{align}$
Hence, $(p+q+12)=12$ in this question.
Note:
Here, A is the centre of the conic, the origin, and as you can see, it bisects every chord that passes through it.
First, let’s find the centre of this conic section. To find this, let’s first see if the equation changes when we replace $x$ with $y$ and vice versa. If the equation remains unchanged, then that means that the centre of the conic is the origin itself.
Let’s exchange $x$ and $y$ in the equation now. Doing so, we get :
${{y}^{2}}+{{x}^{2}}+yx=1$ which is the same as the original question.
Hence, we know that the centre of this conic is in fact the origin.
It is a property of all conics that every chord drawn in the conic that passes through its centre is bisected by the centre of that conic. Applying this property to this question, since we don’t have one particular chord, and it’s any chord passing through the origin, we can say that $(p,q)$ is actually the centre of this conic. Hence, this point should be equal to the origin since that is the centre of this conic.
$\begin{align}
& (p,q)=(0,0) \\
& \Rightarrow p=0,q=0 \\
& \Rightarrow p+q+12=0+0+12=12 \\
\end{align}$
Hence, $(p+q+12)=12$ in this question.
Note:
Here, A is the centre of the conic, the origin, and as you can see, it bisects every chord that passes through it.
Recently Updated Pages
Assertion The resistivity of a semiconductor increases class 13 physics CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
How do you arrange NH4 + BF3 H2O C2H2 in increasing class 11 chemistry CBSE
Is H mCT and q mCT the same thing If so which is more class 11 chemistry CBSE
What are the possible quantum number for the last outermost class 11 chemistry CBSE
Is C2 paramagnetic or diamagnetic class 11 chemistry CBSE
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Difference Between Plant Cell and Animal Cell
Fill the blanks with proper collective nouns 1 A of class 10 english CBSE
What is the color of ferrous sulphate crystals? How does this color change after heating? Name the products formed on strongly heating ferrous sulphate crystals. What type of chemical reaction occurs in this type of change.
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Net gain of ATP in glycolysis a 6 b 2 c 4 d 8 class 11 biology CBSE
What organs are located on the left side of your body class 11 biology CBSE