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Angle of minimum deviation is?

Last updated date: 23rd Feb 2024
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Hint: In order to answer this question, as we know that the minimum deviation is related with the prism, first we will explain the minimum deviation occurs in the prism and then we will also discuss the angle of minimum deviation.

The angle of deviation becomes, minimum for a particular angle of incidence of the incident ray on a prism. The angle of least deviation is the smallest value of the angle of deviation. The angle of deviation through a triangular prism is defined as the angle between the incident ray and the emerging ray $(angle\;\,\delta )$ .
${n_{21}} = \dfrac{{\sin (\dfrac{{A + {D_m}}}{2})}}{{\sin (\dfrac{A}{2})}}$
In minimum deviation, the refracted ray in the prism is parallel to its base. In other words, the light ray is symmetrical about the axis of symmetry of the prism. Also, the angles of refractions are equal i.e. ${r_1}\; = \;{r_2}$ . And, the angle of incidence and angle of emergence equal each other $(i = e)$ .