An automobile vehicle has a mass of 1500 kg. What must be the force between the vehicle and road if the vehicle is to be stopped with a negative acceleration of $2m.{s^{ - 2}}$ ?
Answer
564.9k+ views
Hint: In order to this question, to find the force between the vehicle and road if the vehicle is to be stopped with a negative acceleration of $2m.{s^{ - 2}}$ , We will apply Newton’s second law of motion. And we will also discuss the exact meaning of negative acceleration.
Complete step by step solution:
Given that-
Mass of the automobile vehicle, $m = 1500kg$
Final velocity, $v = 0$ (finally the auto-mobile stops)
Acceleration of the automobile, $a = 2m.{s^{ - 2}}$
We need to find the force between the vehicle and the road if the vehicle is to be stopped with a negative acceleration of $ - 2m.{s^{ - 2}}$ .
By using Newton’s second law of motion:-
$
\therefore Force = mass \times acceleration \\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = 1500 \times ( - 2) = - 3000N \\
$
Hence, the force between the automobile and the road is $ - 3000N$ , in the opposite direction of the auto-mobile’s motion.
Additional Information:- The behaviour of objects for which all existing forces are not balanced is described by Newton's second law of motion. The second rule states that an object's acceleration is determined by two factors: the net force acting on the body and the mass of the body.
Note: Negative acceleration merely denotes the direction of acceleration and might indicate whether an object is speeding up or slowing down. Slowing is defined as an item travelling at a positive velocity with a negative acceleration.
Complete step by step solution:
Given that-
Mass of the automobile vehicle, $m = 1500kg$
Final velocity, $v = 0$ (finally the auto-mobile stops)
Acceleration of the automobile, $a = 2m.{s^{ - 2}}$
We need to find the force between the vehicle and the road if the vehicle is to be stopped with a negative acceleration of $ - 2m.{s^{ - 2}}$ .
By using Newton’s second law of motion:-
$
\therefore Force = mass \times acceleration \\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = 1500 \times ( - 2) = - 3000N \\
$
Hence, the force between the automobile and the road is $ - 3000N$ , in the opposite direction of the auto-mobile’s motion.
Additional Information:- The behaviour of objects for which all existing forces are not balanced is described by Newton's second law of motion. The second rule states that an object's acceleration is determined by two factors: the net force acting on the body and the mass of the body.
Note: Negative acceleration merely denotes the direction of acceleration and might indicate whether an object is speeding up or slowing down. Slowing is defined as an item travelling at a positive velocity with a negative acceleration.
Recently Updated Pages
If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

A car covers the first half distance between two places class 11 physics CBSE

The resultant of two vectors overrightarrow P and overrightarrow class 11 physics CBSE

Find the value of cos 135 class 11 maths CBSE

A mass M is held in place by an applied force F and class 11 physics CBSE

A solution of glucose in water is labelled as 10 dfracwv class 11 chemistry CBSE

Trending doubts
Find the value of the expression given below sin 30circ class 11 maths CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

Bond order ofO2 O2+ O2 and O22 is in order A O2 langle class 11 chemistry CBSE

