Question

An angiospermic plant has to produce 88 viable ovules. How many meiotic divisions will be needed to produce equal number of female gametophytes by this plant?  
A) 88                    
B) 22   
C) 44        
D) 132

Answer 1

Hint: The female gametophyte or embryo sac is found inside the ovule. Typically, each ovule only contains one embryo sac. The meiotic division of the diploid mother cell creates each embryo sac. Four haploid cells are produced at the conclusion of a meiotic division; three of these cells typically degenerate, while one develops into the embryo sac. Therefore, 88 meiotic divisions are needed to make 88 viable embryo sacs.

Step by step solution:
A kind of cell division called meiosis creates four gamete cells and reduces the amount of chromosomes in the parent cell by 50%. The development of sperm and egg cells for sexual reproduction depends on this mechanism.
At each cell pole, a full pair of chromosomes gathers. Each set of chromosomes is surrounded by a membrane to produce two new cell nuclei. Even though this is the final stage of meiosis, cell division is not finished without one more cycle of cytokinesis.
Meiosis is a unique type of cell division that only takes place in the testes and ovaries, the organs that create sperm and eggs, the male and female reproductive cells. each ovule only contains one embryo sac. Four haploid cells are produced at the conclusion of a meiotic division; three of these cells typically degenerate, while one develops into the embryo sac. Therefore, 88 meiotic divisions are needed to make 88 viable embryo sacs.

So, option A is correct.

Note: The female gametophyte, also known as the embryo sac or megagametophyte, develops within the ovule and typically consists of three antipodal cells, one central cell, two synergid cells, and one egg cell.