An aircraft has 120 passenger seats. The number of seats occupied during 100 fights is given below:
No. of Seats 100-104 104-108 108-112 112-116 116-120 Frequency 15 20 32 18 15
Determine the mean of seats occupied over the flights.
| No. of Seats | 100-104 | 104-108 | 108-112 | 112-116 | 116-120 |
| Frequency | 15 | 20 | 32 | 18 | 15 |
Answer
541.8k+ views
Hint: The question is related to the statistics topic. Here we have to determine the mean of seats occupied over the flights using the given table of grouped data. To find the mean we have a formula i.e., \[\overline X = \dfrac{{\sum {{f_i}{x_i}} }}{N}\] , where \[{f_i}\] is frequency, \[{x_i}\] is the midpoint of class-interval and \[N = \sum f \] on substituting all values in formula we get the required solution.
Complete step by step answer:
On observing the question is in the form of grouped data where Grouped data is data that has been organized into a frequency distribution. The direct method to find the mean of grouped data is: We have to take the midpoint of every class interval as \[{x_i}\] by using a formula \[{x_i} = \dfrac{{Upper\,limit - lower\,limit}}{2}\]. Next, multiply these values of \[{x_i}\] with their respective frequencies \[f\]. Take total and apply the formula \[\overline X = \dfrac{{\sum {{f_i}{x_i}} }}{N}\].
Where, \[\overline X \] is the mean of grouped data
\[\sum {{f_i}{x_i}} \]- sum of the product of mid term of class intervals and respective frequencies,
\[N = \sum f \]- The total sum of frequencies.
Now consider the table of given observations.
Now, consider the formula of mean \[\overline X \] is
\[ \Rightarrow \,\,\,\overline X = \dfrac{{\sum {{f_i}{x_i}} }}{N}\]
On substituting the values, we have
\[ \Rightarrow \,\,\,\overline X = \dfrac{{10992}}{{10}}\]
On division, we get
\[ \Rightarrow \,\,\,\overline X = 109.92\]
But seats cannot be in decimal, so the number of seats is 109.
Therefore, the mean number of seats occupied over the flights is 109.
Note: As we know, the Mean is the average of the numbers i.e., a calculated "central" value of a set of numbers. The mean of grouped data can also be find by another method called step deviation method by using a formula \[\overline X = A + \dfrac{{\sum {{f_i}{d_i}} }}{N}\] , where A is assumed mean and \[{d_i}\] is the deviations are taken from assumed mean.
Complete step by step answer:
On observing the question is in the form of grouped data where Grouped data is data that has been organized into a frequency distribution. The direct method to find the mean of grouped data is: We have to take the midpoint of every class interval as \[{x_i}\] by using a formula \[{x_i} = \dfrac{{Upper\,limit - lower\,limit}}{2}\]. Next, multiply these values of \[{x_i}\] with their respective frequencies \[f\]. Take total and apply the formula \[\overline X = \dfrac{{\sum {{f_i}{x_i}} }}{N}\].
Where, \[\overline X \] is the mean of grouped data
\[\sum {{f_i}{x_i}} \]- sum of the product of mid term of class intervals and respective frequencies,
\[N = \sum f \]- The total sum of frequencies.
Now consider the table of given observations.
| No. of seats | Frequency \[\left( f \right)\] | \[{x_i} = \dfrac{{Upper\,limit - lower\,limit}}{2}\] | \[{f_i}{x_i}\] |
| 100-104 | 15 | 102 | 1530 |
| 104-108 | 20 | 106 | 2120 |
| 108-112 | 32 | 110 | 3520 |
| 112-116 | 18 | 114 | 2052 |
| 116-120 | 15 | 118 | 1770 |
| \[N = \sum f = 100\] | \[\sum {{f_i}{x_i}} = 10992\] |
Now, consider the formula of mean \[\overline X \] is
\[ \Rightarrow \,\,\,\overline X = \dfrac{{\sum {{f_i}{x_i}} }}{N}\]
On substituting the values, we have
\[ \Rightarrow \,\,\,\overline X = \dfrac{{10992}}{{10}}\]
On division, we get
\[ \Rightarrow \,\,\,\overline X = 109.92\]
But seats cannot be in decimal, so the number of seats is 109.
Therefore, the mean number of seats occupied over the flights is 109.
Note: As we know, the Mean is the average of the numbers i.e., a calculated "central" value of a set of numbers. The mean of grouped data can also be find by another method called step deviation method by using a formula \[\overline X = A + \dfrac{{\sum {{f_i}{d_i}} }}{N}\] , where A is assumed mean and \[{d_i}\] is the deviations are taken from assumed mean.
Recently Updated Pages
Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Class 11 Question and Answer - Your Ultimate Solutions Guide

Master Class 11 Biology: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Accountancy: Engaging Questions & Answers for Success

Trending doubts
Differentiate between an exothermic and an endothermic class 11 chemistry CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

