Question

Alkaline solution of $ N{H_4}Cl $ gives brown ppt. with $ {K_2}Hg{I_4} $ If the given statement is true enter 1 else enter 0.

Answer 1

Hint :To answer this question, we first need to understand what an alkaline solution is. The solution created when an alkali is dissolved in water is known as alkaline solution. They can be created in a lab or through natural processes such as erosion. Because alkaline solutions are basic in nature, they are employed in laboratories, industries, and other settings to make chemical reactions basic or neutral.

Complete Step By Step Answer:
Precipitate - Precipitation in aqueous solution is the transformation of a dissolved substance into an insoluble solid from a supersaturated solution. The precipitate is the solid that forms. The precipitant is the chemical reagent that causes the solid to develop in an inorganic chemical process that results in precipitation.
The clear liquid remaining above the precipitated or the centrifuged solid phase is the 'supernatant' or 'supernatant’. When solid impurities segregate from a solid phase (e.g., metallurgy and alloys), the concept of precipitation can be extended to other fields of chemistry (organic chemistry and biochemistry) and even applied to solid phases (e.g., metallurgy and alloys).
\[Nessler's{\text{ }}reagent{\text{ }}can{\text{ }}be{\text{ }}prepared{\text{ }}by{\text{ }}using\;KI,Hg{I_2},andNaOHor\;KI(excess),HgC{l_2}andNaOH \\
  Mercuric{\text{ }}chloride{\text{ }}reacts{\text{ }}with{\text{ }}potassium{\text{ }}iodide{\text{ }}to{\text{ }}form{\text{ }}an{\text{ }}orange{\text{ }}ppt{\text{ }}of{\text{ }}mercuric{\text{ }}iodide. \\
  HgC{l_2} + 2KI \to orangeHg{I_2} \downarrow \\
  Mercuric{\text{ }}iodide{\text{ }}reacts{\text{ }}with{\text{ }}KI{\text{ }}to{\text{ }}form{\text{ }}Nessler's{\text{ }}reagent{\text{ }}which{\text{ }}is{\text{ }}soluble{\text{ }}in{\text{ }}water.\; \\
  Hg{I_2} + 2KI \to {K_2}Hg{I_4}(so\operatorname{lub} le) \\
  Nessler's{\text{ }}reagent{\text{ }}is{\text{ }}used{\text{ }}to{\text{ }}identify\;\;N{H^{4 + }}ions. \\
  2{K_2}Hg{I_4} + 4NaOH + N{H_4}Cl \to H{g_2}N{H_2}OI(brown{\kern 1pt} {\kern 1pt} ppt) + 7NaI + KCl + 3{H_2}O \]
So, the final answer is 1.

Note :
A chemical compound is a substance made up of numerous identical molecules bound together by chemical bonds and made up of atoms from different elements. As a result, a molecule made up of only one element's atoms is not a compound.