
After 15 years Meena's age will be \[2\dfrac{1}{2}\] times her present age. Find her present age.
Answer
586.8k+ views
Hint: We have to observe the relation between the age of Meena in different years as given. Through that we will form a linear equation. A linear equation is any equation that can be written in the form \[ax + b = 0\]
where a and b are real numbers and x is a variable.
Using that linear equation, we will solve the question.
Complete step by step answer:
Let Meena’s present age = $x$ years
After 15 years, her age will be = $x + 15$ years
As per the given question:-
$ x + 15 = 2\dfrac{1}{2}x \\$
Solving for the value of $x$
$\Rightarrow x + 15 = \dfrac{5}{2}x \\$
$ \Rightarrow \dfrac{5}{2}x - x = 15 \\$
Simplifying the above equation, we get
$\Rightarrow \dfrac{{5x - 2x}}{2} = 15 \\$
$\Rightarrow \dfrac{{3x}}{2} = 15 \\$
On further simplification,
$\Rightarrow x = 15{\times}\dfrac{2}{3} \\$
On simplifying the above equation,
$ \Rightarrow x = 10 \\ $
$\therefore$ Meena's present age = 10 years
Note:
Verify your answer with the final step. So, you can know whether or not you got the correct answer. We verify the answer by plugging the results from the previous steps into the original equation.
where a and b are real numbers and x is a variable.
Using that linear equation, we will solve the question.
Complete step by step answer:
Let Meena’s present age = $x$ years
After 15 years, her age will be = $x + 15$ years
As per the given question:-
$ x + 15 = 2\dfrac{1}{2}x \\$
Solving for the value of $x$
$\Rightarrow x + 15 = \dfrac{5}{2}x \\$
$ \Rightarrow \dfrac{5}{2}x - x = 15 \\$
Simplifying the above equation, we get
$\Rightarrow \dfrac{{5x - 2x}}{2} = 15 \\$
$\Rightarrow \dfrac{{3x}}{2} = 15 \\$
On further simplification,
$\Rightarrow x = 15{\times}\dfrac{2}{3} \\$
On simplifying the above equation,
$ \Rightarrow x = 10 \\ $
$\therefore$ Meena's present age = 10 years
Note:
Verify your answer with the final step. So, you can know whether or not you got the correct answer. We verify the answer by plugging the results from the previous steps into the original equation.
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