Question

Addition of largest odd numbers and the smallest even number from the integers -5 to 5 is
$
  (a){\text{ 9}} \\
  (b){\text{ - 9}} \\
  (c){\text{ 1}} \\
  (d){\text{ - 1}} \\
 $

Answer 1

Hint: The set of integers between -5 to 5 are (-5, -4, -3, -2, -1, 0, 1, 2, 3, 4 and 5), simply find the largest odd number and the smallest even number amongst them, and then find the sum.

Complete step-by-step answer:

Given set of integers (-5, -4, -3, -2, -1, 0, 1, 2, 3, 4 and 5)
Now as we know that even number are those which are divisible by 2 so from the amongst integers the set of even numbers is
Even numbers = (-4, -2, 2 and 4) as we know 0 is neither even nor odd.
So from the above even numbers the smallest even number is (-4).
Therefore smallest number = -4.
Now as we know odd number are those which is not divisible by 2 so from the amongst integers the set of odd numbers is
Odd numbers = (-5, -3, -1, 1, 3 and 5)
So from the above odd numbers the largest odd number is (5).
Now we have to find out the addition of the largest odd number and smallest even number.
So required addition is = 5 + (-4) = 1.
So this is the required answer.
Hence option (c) is correct.

Note: There must be confusion whether a negative number be even or odd. Yes, a negative number can be categorized into even or odd, following up with the same basic definition of even and odd. Any number ranging from $\left( { - \infty , + \infty } \right)$ can be either odd or even.