
A survey shows that 63% of Americans like cheese whereas 76% like apples. If \[x\% \] of the American like both cheese and apples, then
A. \[x = 39\]
B. \[x = 63\]
C. \[39 \le x \le 63\]
D. None of these
Answer
557.7k+ views
Hint: Here, we have to find the value of the variable \[x\] or the percent of Americans who like both cheese and apples. We will substitute the given values in the set formulas. We will then form an inequality and solve it further to get the range of \[x\].
Formula used: If \[A\] and \[B\] are two sets, then set formula is given by\[n\left( {A \cup B} \right) = n\left( A \right) + n\left( B \right) - n\left( {A \cap B} \right)\].
Complete step by step solution:
Let \[C\] denote the percentage of people who like cheese and let \[A\] denote the percentage of people who like apples.
Then according to question, we have
\[n\left( C \right) = 63\], \[n\left( A \right) = 76\] and \[n\left( {C \cap A} \right) = x\]
Here \[n\left( C \right)\] means the percentage of Americans who like cheese, \[n\left( A \right)\] means the percentage of Americans who like apples and \[n\left( {C \cap A} \right)\] denotes the percentage of Americans who like both cheese and apples.
Using the set formula, \[n\left( {A \cup B} \right) = n\left( A \right) + n\left( B \right) - n\left( {A \cap B} \right)\], for the given data, we get
\[ \Rightarrow n\left( {C \cup A} \right) = n\left( C \right) + n\left( A \right) - n\left( {C \cap A} \right)\]
Now, we will put the values in the formula of the set.
\[ \Rightarrow n\left( {C \cup A} \right) = 63 + 76 - x\]
On further simplification, we get
\[ \Rightarrow n\left( {C \cup A} \right) = 139 - x\] ……. \[\left( 1 \right)\]
We know the value of \[n\left( {C \cup A} \right)\] would be less than or equal to 100 i.e.
\[n\left( {C \cup A} \right) \le 100\]
Substituting the value of \[n\left( {C \cup A} \right)\] from equation \[\left( 1 \right)\] in the above inequality, we get
\[ \Rightarrow 139 - x \le 100\]
Subtracting 139 from sides of inequality, we get
\[\begin{array}{l} \Rightarrow 139 - 139 - x \le 100 - 139\\ \Rightarrow - x \le - 39\end{array}\]
Multiplying \[ - 1\] on both sides, we get
\[ \Rightarrow x \ge 39\]
We also know that \[n(C \cap A) \le n(C)\] and \[n(C \cap A) \le n(A)\] .
Therefore,
\[ \Rightarrow x \le 63\]
Hence, the range of \[x\] is \[39 \le x \le 63\]
Therefore, the correct option is option C.
Note: We need to know the basic property of inequality to find the range of \[x\] here. In mathematics, inequalities are basically used to compare the relative size of two or more values. We need to keep in mind that while multiplying or dividing an inequality by a negative number then the sign of inequality changes. If we don’t change the sign we will get the wrong range of \[x\].
Formula used: If \[A\] and \[B\] are two sets, then set formula is given by\[n\left( {A \cup B} \right) = n\left( A \right) + n\left( B \right) - n\left( {A \cap B} \right)\].
Complete step by step solution:
Let \[C\] denote the percentage of people who like cheese and let \[A\] denote the percentage of people who like apples.
Then according to question, we have
\[n\left( C \right) = 63\], \[n\left( A \right) = 76\] and \[n\left( {C \cap A} \right) = x\]
Here \[n\left( C \right)\] means the percentage of Americans who like cheese, \[n\left( A \right)\] means the percentage of Americans who like apples and \[n\left( {C \cap A} \right)\] denotes the percentage of Americans who like both cheese and apples.
Using the set formula, \[n\left( {A \cup B} \right) = n\left( A \right) + n\left( B \right) - n\left( {A \cap B} \right)\], for the given data, we get
\[ \Rightarrow n\left( {C \cup A} \right) = n\left( C \right) + n\left( A \right) - n\left( {C \cap A} \right)\]
Now, we will put the values in the formula of the set.
\[ \Rightarrow n\left( {C \cup A} \right) = 63 + 76 - x\]
On further simplification, we get
\[ \Rightarrow n\left( {C \cup A} \right) = 139 - x\] ……. \[\left( 1 \right)\]
We know the value of \[n\left( {C \cup A} \right)\] would be less than or equal to 100 i.e.
\[n\left( {C \cup A} \right) \le 100\]
Substituting the value of \[n\left( {C \cup A} \right)\] from equation \[\left( 1 \right)\] in the above inequality, we get
\[ \Rightarrow 139 - x \le 100\]
Subtracting 139 from sides of inequality, we get
\[\begin{array}{l} \Rightarrow 139 - 139 - x \le 100 - 139\\ \Rightarrow - x \le - 39\end{array}\]
Multiplying \[ - 1\] on both sides, we get
\[ \Rightarrow x \ge 39\]
We also know that \[n(C \cap A) \le n(C)\] and \[n(C \cap A) \le n(A)\] .
Therefore,
\[ \Rightarrow x \le 63\]
Hence, the range of \[x\] is \[39 \le x \le 63\]
Therefore, the correct option is option C.
Note: We need to know the basic property of inequality to find the range of \[x\] here. In mathematics, inequalities are basically used to compare the relative size of two or more values. We need to keep in mind that while multiplying or dividing an inequality by a negative number then the sign of inequality changes. If we don’t change the sign we will get the wrong range of \[x\].
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
Differentiate between an exothermic and an endothermic class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

State the laws of reflection of light

