
A square field has area 3,32,929 ${m^2}$. It has to be fenced using barbed wire, the barbed wire should go round the field 5 times. The barbed wire is available in bundles of 100 m length. The vendor sells the wire only in complete bundles. How many bundles have to be bought?
Answer
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Hint: In the above mentioned question area of a square field is given. So, we can find the length of the side of a square field. Now, according to the question square field has to be fenced using barbed wire and barbed wire should go around the field 5 times. Now, we will find the perimeter of a square field to find out the length of wire to be used in fencing a square field. Then we can find the number of bundles that have to be bought for fencing a square field.
Complete step by step solution:
Given,
Area of a square field =$ 3,32,929 {m^2}$.
The length of barbed wire is available in bundles of $100 m$.
Let a be the side of the square.
Area of square = $a \times a = {a^2}$ [Area of square = side × side]
Now, according to the question;
Area of a square field =$ 3,32,929 {m^2}$
$ \Rightarrow {a^2} = 3,32,929$
$\therefore a = 577$m
Side of square = 577 m
Now, Perimeter of square = 4 × side
Perimeter of a square field $ = 4 \times a = 4 \times 577 = 2308$m
Barbed wire goes around the square field 5 times = 2308 X 5 = 11,540 m
Number of bundles to be bought from the vendor = $\dfrac{{11,540}}{{100}}$
$= 115.4 $
On taking the round figure,
$ \Rightarrow 116$ bundles.
$\therefore$ The total number of bundles bought is 116.
Note:
In this question, we need to buy $116$ bundles from the vendor because the barbed wire is available in bundles of 100 m in length. We can’t buy $115.4 m$ wire because we have to buy it in a bundle of $100 m.$
Complete step by step solution:
Given,
Area of a square field =$ 3,32,929 {m^2}$.
The length of barbed wire is available in bundles of $100 m$.
Let a be the side of the square.
Area of square = $a \times a = {a^2}$ [Area of square = side × side]
Now, according to the question;
Area of a square field =$ 3,32,929 {m^2}$
$ \Rightarrow {a^2} = 3,32,929$
$\therefore a = 577$m
Side of square = 577 m
Now, Perimeter of square = 4 × side
Perimeter of a square field $ = 4 \times a = 4 \times 577 = 2308$m
Barbed wire goes around the square field 5 times = 2308 X 5 = 11,540 m
Number of bundles to be bought from the vendor = $\dfrac{{11,540}}{{100}}$
$= 115.4 $
On taking the round figure,
$ \Rightarrow 116$ bundles.
$\therefore$ The total number of bundles bought is 116.
Note:
In this question, we need to buy $116$ bundles from the vendor because the barbed wire is available in bundles of 100 m in length. We can’t buy $115.4 m$ wire because we have to buy it in a bundle of $100 m.$
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