A solution of ethanol in water is 10 % by volume. If the solution and pure ethanol have densities of 0.9866 g/cc and 0.785 g/cc respectively. The percent by weight is nearly?
(A) 7.95 %
(B) 17 %
(C) 9.86 %
(D) 16.2 %
Answer
561.9k+ views
Hint: Solution is represented in terms of relative percent concentration of solute in a solution. This calculation provides information about the concentration of the solution. The percentage expresses the number of parts of a particular substance per 100 total parts.
Complete Solution :
We know that the volume percent is used to express the concentration of a solution when the volume of a solute and the volume of a solution is given.
And we write the equation as:
$\text{Volume}\,\text{percentage=}\dfrac{\text{Volume}\,\text{of}\,\text{solute}}{\text{Volume}\,\text{of}\,\text{solution}}\text{ }\!\!\times\!\!\text{ 100 }\!\!%\!\!\text{ }$
Since it is given that, 10% of the total solution has ethanol.
Now take the total volume of solution as 100ml, then the volume of ethanol will be 10ml.
Volume of ethanol = 10ml
Volume of solution = 100ml
$\text{Density =}\dfrac{\text{Mass}}{\text{Volume}}$
By rearranging the above equation, the mass of ethanol and solution can be derived.
And the equation becomes,
Weight of ethanol = Volume$\times$density
Weight of ethanol = $10\times 0.785=7.85g$
Weight of solution = $100\times 0.9866=98.66g$
$\text{Weight}\,\text{percent}\,\text{of}\,\text{ethanol=}\dfrac{\text{Weight}\,\text{of}\,\text{ethanol}}{\text{Weight}\,\text{of}\,\text{solution}}\text{ }\!\!\times\!\!\text{ 100 }\!\!%\!\!\text{ }$
Weight percent of ethanol = $\dfrac{7.85}{98.66}\times 100%$
Weight percent of ethanol = 7.95%
So, the correct answer is “Option A”.
Note: We generally express concentration in terms of relative units. And the three different types of percentage concentration which is commonly used are as follows:
1. Mass percent: The mass percent is used to express the concentration of a solution when the mass of a solute and the mass of solution is given.
2. Volume percent: The volume percent is commonly used to express the concentration of a solution when the volume of a solute and the volume of a solution is provided.
3. Mass/Volume percent: This measures the mass or weight of solute in grams vs. the volume of solution.
Complete Solution :
We know that the volume percent is used to express the concentration of a solution when the volume of a solute and the volume of a solution is given.
And we write the equation as:
$\text{Volume}\,\text{percentage=}\dfrac{\text{Volume}\,\text{of}\,\text{solute}}{\text{Volume}\,\text{of}\,\text{solution}}\text{ }\!\!\times\!\!\text{ 100 }\!\!%\!\!\text{ }$
Since it is given that, 10% of the total solution has ethanol.
Now take the total volume of solution as 100ml, then the volume of ethanol will be 10ml.
Volume of ethanol = 10ml
Volume of solution = 100ml
$\text{Density =}\dfrac{\text{Mass}}{\text{Volume}}$
By rearranging the above equation, the mass of ethanol and solution can be derived.
And the equation becomes,
Weight of ethanol = Volume$\times$density
Weight of ethanol = $10\times 0.785=7.85g$
Weight of solution = $100\times 0.9866=98.66g$
$\text{Weight}\,\text{percent}\,\text{of}\,\text{ethanol=}\dfrac{\text{Weight}\,\text{of}\,\text{ethanol}}{\text{Weight}\,\text{of}\,\text{solution}}\text{ }\!\!\times\!\!\text{ 100 }\!\!%\!\!\text{ }$
Weight percent of ethanol = $\dfrac{7.85}{98.66}\times 100%$
Weight percent of ethanol = 7.95%
So, the correct answer is “Option A”.
Note: We generally express concentration in terms of relative units. And the three different types of percentage concentration which is commonly used are as follows:
1. Mass percent: The mass percent is used to express the concentration of a solution when the mass of a solute and the mass of solution is given.
2. Volume percent: The volume percent is commonly used to express the concentration of a solution when the volume of a solute and the volume of a solution is provided.
3. Mass/Volume percent: This measures the mass or weight of solute in grams vs. the volume of solution.
Recently Updated Pages
Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

Find the value of the expression given below sin 30circ class 11 maths CBSE

Two of the body parts which do not appear in MRI are class 11 biology CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

