Question

A shopkeeper purchased 364 kg 500 g of orange. Later on, he found that 109 kg 300 g of orange were rotten. Find the quantity of orange in good conditions.
A.\[150\text{ }kg\text{ }670\text{ }g.~\]
B. \[204\text{ }kg\text{ }600\text{ }g.\]
C. \[237\text{ }kg\text{ }200\text{ }g.\]
D. \[250\text{ }kg\text{ }940\text{ }g.\]

Answer 1

Hint: In the question we are asked to find the quantity of orange in good condition. To find this we need to subtract the quantity of rotten oranges from the quantity of purchased oranges.

Complete step-by-step answer:
It is given that the total weight of oranges purchased \[=\text{ }346\text{ }kg\text{ }500\text{ }g.\] and total weight of rotten oranges \[=\text{ }109\text{ }kg\text{ }300\text{ }g.\]
We have been asked to find the number of oranges in good conditions. So, we have to subtract the number of rotten oranges from the number of purchased oranges.
Here, we can write the given weight \[346kg.500g\] as \[346kg+500g\] and,
\[109kg.300g\] as \[109kg+300\text{ }g.\]
Thus, purchased oranges – rotten oranges
$\begin{align}
  & =\left[ 346kg+500g \right]-\left[ 109kg+300g \right]. \\
 & =\left[ 346kg-109kg \right]+\left[ 500g-300g \right]. \\
 & =\left[ 237kg+200g \right]. \\
\end{align}$
Therefore, \[237\text{ }kg.200\text{ }g\] are the oranges of good conditions.
Hence, option (c) is the correct answer.

Note: Students can solve this problem in an alternative way. The weight of the oranges is given in two different units, so we can convert them to a single unit. We can use the conversion $1kg=1000g$ . Then we can perform the subtraction and again write it as separate units to match the options. But, this method is a long way to solve this question, so we must avoid it.