
A shopkeeper marked his price for Rs.150. He pays a customer a 10% discount and a second discount 5%. What does he get?
Answer
605.7k+ views
HINT: - The first discount is applied on the initial marked price. Then, if there is any second discount, it will then be applied on the marked price which is equal to the initial marked price – (the discount).
The formula for finding x percentage of any quantity 1 is
\[\dfrac{x}{100}\times Quantity\ 1\]
Complete step-by-step solution -
As per the question, the shopkeeper has marked the price as Rs. 150 that is the marked price of the item is Rs. 150.
Using the formula given in the hint, we can write as follows
The discount is applied on the marked price and the new marked price would be
Initial marked price – (discount) that is the new marked price is
\[\begin{align}
& =150-\dfrac{10}{100}\times 150 \\
& =150-15 \\
& =Rs.135 \\
\end{align}\]
Now, the second discount will be imposed on the new marked price so, we get
\[\begin{align}
& =135-\dfrac{5}{100}\times 135 \\
& =135-6.75 \\
& =Rs.128.25 \\
\end{align}\]
Hence, the shopkeeper finally gets Rs.128.25.
NOTE: - The only step at which the student can make an error is where the second discount is to be applied on the item.
The students can make an error if they do not change the marked price or if they do not apply the second discount on the new marked price which is the initial marked price-(first discount).
The formula for finding x percentage of any quantity 1 is
\[\dfrac{x}{100}\times Quantity\ 1\]
Complete step-by-step solution -
As per the question, the shopkeeper has marked the price as Rs. 150 that is the marked price of the item is Rs. 150.
Using the formula given in the hint, we can write as follows
The discount is applied on the marked price and the new marked price would be
Initial marked price – (discount) that is the new marked price is
\[\begin{align}
& =150-\dfrac{10}{100}\times 150 \\
& =150-15 \\
& =Rs.135 \\
\end{align}\]
Now, the second discount will be imposed on the new marked price so, we get
\[\begin{align}
& =135-\dfrac{5}{100}\times 135 \\
& =135-6.75 \\
& =Rs.128.25 \\
\end{align}\]
Hence, the shopkeeper finally gets Rs.128.25.
NOTE: - The only step at which the student can make an error is where the second discount is to be applied on the item.
The students can make an error if they do not change the marked price or if they do not apply the second discount on the new marked price which is the initial marked price-(first discount).
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