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# A plane is flying at the height of $5000 m$ above the sea level. At a particular point, it is exactly above a submarine floating $1200 m$ below the sea level. What is the vertical distance between them?

Last updated date: 18th Sep 2024
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Hint: The height above the sea level is taken as positive and the height below the sea level is taken as negative. For the measurement of vertical distance between them we take the modulus of the negative height and then add both the heights.

Given the height of the plane is 5000 m above the sea level.
Let us denote this height with ${h_1} = + 5000m$.
The depth of the submarine below the sea is 1200 metres below the sea level.
Let us denote this distance with ${h_2} = - 1200m$
Since this distance is below the sea level we take the modulus.
$D = {h_1} + |{h_2}| \\ \Rightarrow D = 5000 + | - 1200| \\ \therefore D = 5000 + 1200 = 6200m \\$
Therefore the vertical distance(D) between the plane and the submarine is 6200m.