Answer

Verified

429k+ views

**Hint:**In this question, we need to evaluate the options such that when the monkey climbs the rope, when will the rope break. For this, we will follow the free body diagram of the monkey and the rope and apply the newton’s equation of motion.

**Complete step by step answer:**

According to the conditions given in the question, the free body diagram is sketched as below.

Here, due to the mass of the money, a gravitational force always acts downwards, which is equivalent to the product of the mass of the monkey and the acceleration due to gravity. Mathematically, ${F_d} = mg$.

The mass of the monkey has been given as 40 kg, so the gravitational force acting downwards is given as:

$

\Rightarrow{F_d} = 40g \\

\Rightarrow{F_d} = 40 \times 10 \\

\Rightarrow{F_d} = 400N \\

$

Now, we will proceed with the observation for each of the given options:

(A) When the monkey climbs up with the uniform velocity of $5{\text{ m/sec}}$ then, the acceleration of the monkey will be zero. Hence the net force acting will be 400N only, which is smaller than the tensile strength of the rope and so the rope will not break.

(B) When the monkey climbs up with an acceleration of $6{\text{ m/se}}{{\text{c}}^2}$ then, the net force acting on the rope is calculated as:

$

\Rightarrow{F_r} = ma + mg \\

\Rightarrow{F_r} = 40(6 + 10) \\

\Rightarrow{F_r} = 40 \times 16 \\

\Rightarrow{F_r} = 640N \\

$

But, the tensile strength of the rope is 600N, and so, the rope will break.

(C) When the monkey climbs down with an acceleration of $4{\text{ m/se}}{{\text{c}}^2}$ then, the net force acting on the rope is calculated as:

$

\Rightarrow{F_r} = mg - ma \\

\Rightarrow{F_r} = 40(10 - 4) \\

\Rightarrow{F_r} = 40 \times 6 \\

\Rightarrow{F_r} = 240N \\

$

But, the tensile strength of the rope is 600N, and so, the rope will not break.

(D) When the monkey climbs down with the uniform velocity of $5{\text{ m/sec}}$ then, the acceleration of the monkey will be zero. Hence the net force acting will be 400N only, which is smaller than the tensile strength of the rope, and so the rope will not break.Hence, the rope will break only under one condition, i.e., when the monkey climbs up with an acceleration of $6{\text{ m/se}}{{\text{c}}^2}$.

**Hence,option B is correct.**

**Note:**It is worth noting down here that we have taken the absolute value of the acceleration due to gravity as 10 instead of 9.8 as it is mentioned in the question. Moreover, when a body is moving with the constant velocity then, the acceleration of the body is zero only as the acceleration is defined as the rate of change of velocity with respect to time.

Recently Updated Pages

Mark and label the given geoinformation on the outline class 11 social science CBSE

When people say No pun intended what does that mea class 8 english CBSE

Name the states which share their boundary with Indias class 9 social science CBSE

Give an account of the Northern Plains of India class 9 social science CBSE

Change the following sentences into negative and interrogative class 10 english CBSE

Advantages and disadvantages of science

Trending doubts

Which are the Top 10 Largest Countries of the World?

Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE

Fill the blanks with the suitable prepositions 1 The class 9 english CBSE

Give 10 examples for herbs , shrubs , climbers , creepers

Write a letter to the principal requesting him to grant class 10 english CBSE

How do you graph the function fx 4x class 9 maths CBSE

The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths

10 examples of evaporation in daily life with explanations