Question

When a hollow steel ball and a solid steel ball of same size are submerged in water, do the two experience the same upthrust.

Answer 1

Hint:The upthrust or the buoyant force is the upward force experienced by the object, when the object is completely or partially immersed. The Archimedes’ principle states that when a body is immersed fully or completely. The body will experience an upthrust which is equal to the weight of the liquid displaced by it.

Complete answer:
When an object of volume $V$ and density $\rho $ is immersed in a liquid of density ${\rho _L}$.If $g$ is the acceleration due to gravity. The weight of the body is given by $V\rho g$.The upthrust or buoyant force on the body is given by $V{\rho _L}g$. From this equation it is clear that upthrust or buoyant force depends on following factors:
-The density of fluid displaced.
-The volume of the body.
-Weight of the liquid displaced.

Since both hollow steel ball and solid steel ball have the same volume when it is submerged in the water. Hence both hollow steel ball and a solid steel ball will experience the same thrust.

Note:Due to the upthrust or buoyant force, a body or an object immersed partially or fully in a fluid appears to be lighter, that is the will appears to be reduced. Suppose if the upthrust is less than the weight of the object, the object will sink.