
A coin is tossed three times. Find the probability of the following events.
(1) A: getting at least two heads
(2) B: getting exactly two heads.
(3) C: getting at most one head.
Answer
530.1k+ views
Hint: A coin is tossed three times, so the sample space: , so, total number of possible outcomes = 8. Use the formula, , where number of favourable outcomes means the outcomes which may take place for that event and total number of possible outcomes means the total possibilities that may occur when a coin is tossed three times. According to given cases find the number of favourable outcomes and probability of that particular case.
Complete step-by-step answer:
(1) A: getting at least two heads
Now for getting two heads, the number of favourable outcomes will be 3 which are .
And the total no. of possible outcomes is 8 which are .
Now for getting three heads, no. of favourable outcomes will be 1 which is .
Therefore, probability is-
(using formula )
(2) B: getting exactly two heads
Now for getting two heads, no. of favourable outcomes will be 3 which are .
And the total no. of possible outcomes is 8 which are .
Therefore, the probability is-
(using formula )
(3) C: getting at most one head.
Getting atmost one head means number of heads can be 0 or 1 i.e getting no head and one head
Now for getting no heads, no. of favourable outcomes will be 1 which is .
And the total no. of possible outcomes is 8 which are .
Now for getting one head, no. of favourable outcomes will be 4 which is .
Therefore, probability is-
(using formula )
Note- Whenever such a type of question appears note down all the outcomes of the event and the possible outcomes in the particular given case, as given in question the coin is tossed 3 times. And then find the probability of all the cases using the standard formula.
Complete step-by-step answer:
(1) A: getting at least two heads
Now for getting two heads, the number of favourable outcomes will be 3 which are
And the total no. of possible outcomes is 8 which are
Now for getting three heads, no. of favourable outcomes will be 1 which is
Therefore, probability is-
(2) B: getting exactly two heads
Now for getting two heads, no. of favourable outcomes will be 3 which are
And the total no. of possible outcomes is 8 which are
Therefore, the probability is-
(3) C: getting at most one head.
Getting atmost one head means number of heads can be 0 or 1 i.e getting no head and one head
Now for getting no heads, no. of favourable outcomes will be 1 which is
And the total no. of possible outcomes is 8 which are
Now for getting one head, no. of favourable outcomes will be 4 which is
Therefore, probability is-
(using formula
Note- Whenever such a type of question appears note down all the outcomes of the event and the possible outcomes in the particular given case, as given in question the coin is tossed 3 times. And then find the probability of all the cases using the standard formula.
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