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A coin is tossed three times. Find the probability of the following events.
(1) A: getting at least two heads
(2) B: getting exactly two heads.
(3) C: getting at most one head.

Answer
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Hint: A coin is tossed three times, so the sample space:{HHH,HTH,THH,TTH,HHT,HTT,THT,TTT}, so, total number of possible outcomes = 8. Use the formula, P(event)=No.ofFavourableOutcomesTotalNo.ofPossibleOutcomes, where number of favourable outcomes means the outcomes which may take place for that event and total number of possible outcomes means the total possibilities that may occur when a coin is tossed three times. According to given cases find the number of favourable outcomes and probability of that particular case.

Complete step-by-step answer:
(1) A: getting at least two heads
 P(A)=P(GettingTwoHeads)+P(GettingThreeHeads)
Now for getting two heads, the number of favourable outcomes will be 3 which are {HTH,THH,HHT}.
And the total no. of possible outcomes is 8 which are {HHH,HTH,THH,TTH,HHT,HTT,THT,TTT}.
Now for getting three heads, no. of favourable outcomes will be 1 which is {HHH}.
Therefore, probability is-
 P(A)=38+18=48=12 (using formula P(event)=No.ofFavourableOutcomesTotalNo.ofPossibleOutcomes)
P(A)=12

(2) B: getting exactly two heads
Now for getting two heads, no. of favourable outcomes will be 3 which are {HTH,THH,HHT}.
And the total no. of possible outcomes is 8 which are {HHH,HTH,THH,TTH,HHT,HTT,THT,TTT}.
Therefore, the probability is-
P(B)=P(GettingExactlyTwoHeads)P(B)=38 (using formula P(event)=No.ofFavourableOutcomesTotalNo.ofPossibleOutcomes)

(3) C: getting at most one head.
Getting atmost one head means number of heads can be 0 or 1 i.e getting no head and one head

Now for getting no heads, no. of favourable outcomes will be 1 which is {TTT}.
And the total no. of possible outcomes is 8 which are {HHH,HTH,THH,TTH,HHT,HTT,THT,TTT}.
Now for getting one head, no. of favourable outcomes will be 4 which is {HTT,THT,TTT}.
Therefore, probability is-
 (using formula P(event)=No.ofFavourableOutcomesTotalNo.ofPossibleOutcomes)
P(C)=P(GettingNoHeads)+P(GettingOneHeads)P(C)=18+38=48=12P(C)=12

Note- Whenever such a type of question appears note down all the outcomes of the event and the possible outcomes in the particular given case, as given in question the coin is tossed 3 times. And then find the probability of all the cases using the standard formula.
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