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A book with many printing errors contains four different formulas for the displacement y of a particle undergoing certain periodic motion:
1) y=asin2πt/T
2) y=asinvt
3) y=(a/T)sint/a
4) y=(a/2)(sin2π/T+cos2π/T)
(a = maximum displacement of the particle, v = speed of the particle. AT = time period of motion). Rule out the wrong formulas on dimensional grounds.

Answer
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Hint:-Dimensional analysis is being used to check the equation if it is correct or not. If the dimensions in the LHS and RHS are equal then the equation is said to be correct if not then it is not correct.

Complete step-by-step solution:
Step1: Dimensional Analysis ofy=asin2πt/T. Here the dimensions on the LHS must be equal to the dimension on the RHS.
y=asin2πt/T;
L1=L1;
Functions that are trigonometric generally are dimensionless, so 2πtTwill also be a dimensionless quantity.
2πtT=TT=M0L0T0;
Hence the dimensions are correct, so, this formula is dimensionally right.

Step2: Dimensional Analysis ofy=asinvt. Here the dimensions on the LHS must be equal to the dimension on the RHS.
y=asinvt;
Here the amplitude will have the same dimension as length.
L1=L1;
Now, Distance = velocity×Time. SoL=vt;
vt=L1T1T1;
vt=L1T1T1=M0L1T0;
M0L1T0M0L0T0;
This is not a dimensionally right formula;
Step3: Dimensional Analysis ofy=(a/T)sint/a. Here the dimensions on the LHS must be equal to the dimension on the RHS.
y=(a/T)sint/a;
y=(aT)=(L1T1)=(L1T1);
L1(L1T1);
The formula y=(a/T)sint/ais not dimensionally correct.
Step4: Dimensional Analysis ofy=(a/2)(sin2π/T+cos2π/T). Here the dimensions on the LHS must be equal to the dimension on the RHS.
y=(a/2)(sin2π/T+cos2π/T);
L1=L1;
(2πtT)=(TT)=1=M0L0T0;
The formula y=(a/2)(sin2π/T+cos2π/T)is dimensionally correct.

Final Answer: Option “2 and 3” is incorrect.

Note:- Here one has to dimensionally analyze each and every option that is available. Then we have to compare if the dimensions on the LHS and RHS are equal. Every equation that is used in the world of physics has to be dimensionally correct.