A boat is moving towards east with velocity \[4m/s\] wrt still water and river is flowing towards north with velocity \[2m/s\] and the wind is blowing towards north with velocity \[6m/s\].
Answer
537.9k+ views
Hint: We will try to understand the question first then arrange each data one by one and finally by applying \[6m/s\] and many other formulas along with this we will get the accurate answer.
Complete answer:
The velocity of boat with respect to river or Vbr\[ = 4 \uparrow .\] Let us assume that East is our X axis is North is our Y axis. Velocity or river or \[{V_r} = 2 \uparrow \]
Here,
\[
{V_b} = 2 \uparrow + 4J \\
\overrightarrow {{V_b}_r} = {\overrightarrow V _b} - \overrightarrow {{V_r}} \\
\overrightarrow {{V_b}} = \overrightarrow {{V_{br}}} + \overrightarrow {{V_r}} \\
\]
Velocity of wind \[\left( {{V_w}} \right) = 6J\]
Velocity of wind with respect to the boat is referred as \[\left( {{V_{wb}}} \right)\]
\[
\therefore \overrightarrow {{V_{wb}}} = \overrightarrow {{V_w}} - \overrightarrow {{V_b}} \\
= 6J - \left( {2 \uparrow + 4J} \right) \\
= - 2 \uparrow + 2J \\
\]
\[\therefore \]Direction of the flag is in the North West.
Hence, the correct answer is North West direction.
Note: Boat velocity is \[4m/s\] towards east is \[4J\]. Velocity of wind is \[6m/s\]. To solve the other boat problems, we need to understand other many formulas for eg: The speed of a boat relative to the water is equal to the speed of the boat in still water.
Complete answer:
The velocity of boat with respect to river or Vbr\[ = 4 \uparrow .\] Let us assume that East is our X axis is North is our Y axis. Velocity or river or \[{V_r} = 2 \uparrow \]
Here,
\[
{V_b} = 2 \uparrow + 4J \\
\overrightarrow {{V_b}_r} = {\overrightarrow V _b} - \overrightarrow {{V_r}} \\
\overrightarrow {{V_b}} = \overrightarrow {{V_{br}}} + \overrightarrow {{V_r}} \\
\]
Velocity of wind \[\left( {{V_w}} \right) = 6J\]
Velocity of wind with respect to the boat is referred as \[\left( {{V_{wb}}} \right)\]
\[
\therefore \overrightarrow {{V_{wb}}} = \overrightarrow {{V_w}} - \overrightarrow {{V_b}} \\
= 6J - \left( {2 \uparrow + 4J} \right) \\
= - 2 \uparrow + 2J \\
\]
\[\therefore \]Direction of the flag is in the North West.
Hence, the correct answer is North West direction.
Note: Boat velocity is \[4m/s\] towards east is \[4J\]. Velocity of wind is \[6m/s\]. To solve the other boat problems, we need to understand other many formulas for eg: The speed of a boat relative to the water is equal to the speed of the boat in still water.
Recently Updated Pages
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

State and prove Bernoullis theorem class 11 physics CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

