A, B and C are the voltmeters of resistance 1R, 1.5R and 3R respectively as shown in the figure. When some potential difference is applied between X and Y, the voltmeter reading are \[{{V}_{A}}\], \[{{V}_{B}}\] and \[{{V}_{C}}\] respectively. Then
A. \[{{V}_{A}}={{V}_{B}}\ne {{V}_{C}}\]
B. \[{{V}_{A}}\ne {{V}_{B}}\ne {{V}_{C}}\]
C. \[{{V}_{A}}={{V}_{B}}={{V}_{C}}\]
D. \[{{V}_{A}}\ne {{V}_{B}}\ne {{V}_{C}}\]
Answer
608.7k+ views
Hint: In this question we are being asked the relation between \[{{V}_{A}}\],\[{{V}_{B}}\]and \[{{V}_{C}}\]. As we can see from the figure the resistor B and C are parallel. Therefore, we will have to calculate the equivalent resistance. The circuit is said to be given some potential difference. After calculating the equivalent resistance we can state the relation by using the Ohm’s law.
Formula used:
V = IR
Where V is the potential difference, R is the resistance and I is the current flowing through the circuit.
Complete step-by-step answer:
We have been given that resistance in A is R and that in B and C is 1.5R and 3R respectively. From the diagram we can see that resistance B is parallel to C. Therefore,
We know, the equivalent resistance for resistors in parallel combination is given by,
\[\dfrac{1}{{{R}_{eq}}}=\dfrac{1}{{{R}_{1}}}+\dfrac{1}{{{R}_{2}}}\]
Where,
\[{{R}_{eq}}\] = the equivalent resistance
\[{{R}_{1}}\] = resistance in B
\[{{R}_{2}}\] = resistance in C
Therefore, after substituting values in above equation we get,
\[\dfrac{1}{{{R}_{eq}}}=\dfrac{1}{1.5R}+\dfrac{1}{3R}\]
On solving above equation
We get,
\[\dfrac{1}{{{R}_{eq}}}=\dfrac{3}{3R}\]
Therefore,
\[{{R}_{eq}}=R\]………….. (1)
Now we know from ohm’s law
V = IR
Here we shall assume that current is the same throughout the circuit.
Therefore, we can say that potential difference is directly proportional to resistance.
\[V\propto R\]
From (1) we can say that equivalent resistance of B and C is R which is also the resistance for A. It means that resistance in every branch is equal to A.
Therefore, we can say that potential difference is same across A, B and C i.e. \[{{V}_{A}}={{V}_{B}}={{V}_{C}}\].
So, the correct answer is “Option C”.
Note: A voltmeter is the electric device that is used to measure the potential difference across two points in an electric circuit. Voltmeters show the deflection through the needle. They also show the direction of voltage applied. The voltmeter is always connected in parallel with the points between which the potential difference is to be measured.
Formula used:
V = IR
Where V is the potential difference, R is the resistance and I is the current flowing through the circuit.
Complete step-by-step answer:
We have been given that resistance in A is R and that in B and C is 1.5R and 3R respectively. From the diagram we can see that resistance B is parallel to C. Therefore,
We know, the equivalent resistance for resistors in parallel combination is given by,
\[\dfrac{1}{{{R}_{eq}}}=\dfrac{1}{{{R}_{1}}}+\dfrac{1}{{{R}_{2}}}\]
Where,
\[{{R}_{eq}}\] = the equivalent resistance
\[{{R}_{1}}\] = resistance in B
\[{{R}_{2}}\] = resistance in C
Therefore, after substituting values in above equation we get,
\[\dfrac{1}{{{R}_{eq}}}=\dfrac{1}{1.5R}+\dfrac{1}{3R}\]
On solving above equation
We get,
\[\dfrac{1}{{{R}_{eq}}}=\dfrac{3}{3R}\]
Therefore,
\[{{R}_{eq}}=R\]………….. (1)
Now we know from ohm’s law
V = IR
Here we shall assume that current is the same throughout the circuit.
Therefore, we can say that potential difference is directly proportional to resistance.
\[V\propto R\]
From (1) we can say that equivalent resistance of B and C is R which is also the resistance for A. It means that resistance in every branch is equal to A.
Therefore, we can say that potential difference is same across A, B and C i.e. \[{{V}_{A}}={{V}_{B}}={{V}_{C}}\].
So, the correct answer is “Option C”.
Note: A voltmeter is the electric device that is used to measure the potential difference across two points in an electric circuit. Voltmeters show the deflection through the needle. They also show the direction of voltage applied. The voltmeter is always connected in parallel with the points between which the potential difference is to be measured.
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