
A 500 g toothpaste sample has 0.02 g fluoride concentration. What is the concentration of fluorine in terms of ppm levels?
A ) 250
B ) 40
C ) 400
D ) 1000
Answer
584.1k+ views
Hint: PPM represents parts per million. It is the mass of solute (in grams) present in \[{10^6}{\text{g}}\] of solution. Use the following formula for ppm.
\[{\text{ ppm }} = {\text{ }}\dfrac{{{\text{Mass of solute }}}}{{{\text{Mass of solution }}}}{\text{ }} \times {\text{ 1}}{{\text{0}}^6}\]
Complete step by step answer:
The mass of a sample of toothpaste 500 g. The mass of fluoride ions in the sample of toothpaste is 0.02 g. Calculate the concentration of fluorine in terms of ppm levels.
\[{\text{ ppm }} = {\text{ }}\dfrac{{{\text{Mass of solute }}}}{{{\text{Mass of solution }}}}{\text{ }} \times {\text{ 1}}{{\text{0}}^6} \\
{\text{ ppm }} = {\text{ }}\dfrac{{{\text{0}}{\text{.02 }}}}{{{\text{500 }}}}{\text{ }} \times {\text{ 1}}{{\text{0}}^6} \\
{\text{ ppm }} = {\text{ 40 ppm}} \\\]
Hence, the fluoride ion concentration in the toothpaste sample is 40 ppm.
The concentration of 40 ppm for fluoride ions in the toothpaste means that the mass of fluoride ions present in \[{10^6}{\text{g}}\] of toothpaste sample is 40 g.
Hence, the correct option is the option B ).
Additional Information: ppm can also be expressed in the units of mg/kg or µg/kg.
Thus, one ppm represents 1 mg of solute present in 1 kg of solution.
Note: While expressing the concentration in ppm, the amount of solute can be expressed in either grams or millilitre. Similarly the amount of solution can be expressed in either grams or millilitre. Thus ppm is the mass of solute (in grams) present in \[{10^6}{\text{g}}\] of solution. Also, ppm is the volume (in millilitres) of solute present in \[{10^6}{\text{mL}}\] of solution.
\[{\text{ ppm }} = {\text{ }}\dfrac{{{\text{Mass of solute }}}}{{{\text{Mass of solution }}}}{\text{ }} \times {\text{ 1}}{{\text{0}}^6}\]
Complete step by step answer:
The mass of a sample of toothpaste 500 g. The mass of fluoride ions in the sample of toothpaste is 0.02 g. Calculate the concentration of fluorine in terms of ppm levels.
\[{\text{ ppm }} = {\text{ }}\dfrac{{{\text{Mass of solute }}}}{{{\text{Mass of solution }}}}{\text{ }} \times {\text{ 1}}{{\text{0}}^6} \\
{\text{ ppm }} = {\text{ }}\dfrac{{{\text{0}}{\text{.02 }}}}{{{\text{500 }}}}{\text{ }} \times {\text{ 1}}{{\text{0}}^6} \\
{\text{ ppm }} = {\text{ 40 ppm}} \\\]
Hence, the fluoride ion concentration in the toothpaste sample is 40 ppm.
The concentration of 40 ppm for fluoride ions in the toothpaste means that the mass of fluoride ions present in \[{10^6}{\text{g}}\] of toothpaste sample is 40 g.
Hence, the correct option is the option B ).
Additional Information: ppm can also be expressed in the units of mg/kg or µg/kg.
Thus, one ppm represents 1 mg of solute present in 1 kg of solution.
Note: While expressing the concentration in ppm, the amount of solute can be expressed in either grams or millilitre. Similarly the amount of solution can be expressed in either grams or millilitre. Thus ppm is the mass of solute (in grams) present in \[{10^6}{\text{g}}\] of solution. Also, ppm is the volume (in millilitres) of solute present in \[{10^6}{\text{mL}}\] of solution.
Recently Updated Pages
Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Business Studies: Engaging Questions & Answers for Success

Trending doubts
Why cannot DNA pass through cell membranes class 12 biology CBSE

Differentiate between insitu conservation and exsitu class 12 biology CBSE

Draw a neat and well labeled diagram of TS of ovary class 12 biology CBSE

In a human foetus the limbs and digits develop after class 12 biology CBSE

AABbCc genotype forms how many types of gametes a 4 class 12 biology CBSE

The correct structure of ethylenediaminetetraacetic class 12 chemistry CBSE

