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A 2.16 g of a substance occupies 1.5 $c{{m}^{3}}$ . Its density to appropriate significant figure is:

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Last updated date: 25th Jul 2024
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Answer
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Hint: The density can be defined as the ratio of the mass to the volume. The representation of the density is as follows.
\[\rho =\dfrac{M}{V}\]
$\rho $ = density of the substance
M = Mass of the substance
V = volume of the substance.

Complete answer:
- In the question it is asked to calculate the appropriate significant figure of the density of a substance having 2.16 g and which is going to occupy 1.5 $c{{m}^{3}}$ .
- We should use the density formula to calculate the density by using the mass and the volume.
\[\rho =\dfrac{M}{V}\]
$\rho $ = density of the substance
M = Mass of the substance = 2.16 g
V = volume of the substance = 1.5 $c{{m}^{3}}$
- Substitute all the known values in the above to get the density of the substance and it is as follows.
\[\begin{align}
  & \rho =\dfrac{M}{V} \\
 & \rho =\dfrac{2.16}{1.5}=1.44 \\
\end{align}\]
- The density of the substance is 1.44.
- We can see that there are three significant figures in the density of the substance which is having three significant figures in mass and two significant figures in volume.
- The density in the appropriate significant figure is 1.44.

Note:
As the mass of the substance is going to increase then the density of the substance also increases because the density and the mass of the substance are directly proportional to each other and as the volume increases then the density of the substance is going to decrease because density and the volume are inversely proportional to each other.