
2 tables and 3 chairs together cost $Rs.2000$ whereas 3 tables and 2 chairs together cost $Rs.2500$. Find the total cost of 1 table and 5 chairs.
Answer
613.8k+ views
Hint: To find the total cost of 1 table and 5 chairs, consider the cost of a table as $Rs.x$ and cost of a chair as $Rs.y$. After that, apply the conditions and we will get the answer.
Complete step-by-step answer:
We have been given the cost of 2 tables and 3 chairs together as $Rs.2000$ and also the cost of 3 tables and 2 chairs together is given as $Rs.2500$. We have to formulate equations using the method given below.
Let the cost of a table be $Rs.x$ and the cost of a chair be $Rs.y$.
According to the condition given in the question,
$2x+3y=2000.........\left( 1 \right)$
$3x+2y=2500.........\left( 2 \right)$
Now, let us solve these two linear equations.
Multiplying equation (1) by 3 and equation (2) by 2, we get,
$6x+9y=6000.........\left( 3 \right)$
$6x+4y=5000.........\left( 4 \right)$
Now subtracting equation (4) from equation (3), we get,
$5y=1000$
$y=200$
Now substituting $y=200$ in equation (3) we get,
$x=700$
Now, we want to find the total cost of 1 table and 5 chairs.
So it becomes, $x+5y=700+5\times 200=1700$.
Therefore we have found out the total cost of 1 table and 5 chairs as $Rs.1700$.
Note: Read the question and see what is asked. Concepts regarding word problems should be clear. A proper assumption should be made. Do not make silly mistakes while substituting. Equate it in a proper manner in order to avoid mistakes.
Complete step-by-step answer:
We have been given the cost of 2 tables and 3 chairs together as $Rs.2000$ and also the cost of 3 tables and 2 chairs together is given as $Rs.2500$. We have to formulate equations using the method given below.
Let the cost of a table be $Rs.x$ and the cost of a chair be $Rs.y$.
According to the condition given in the question,
$2x+3y=2000.........\left( 1 \right)$
$3x+2y=2500.........\left( 2 \right)$
Now, let us solve these two linear equations.
Multiplying equation (1) by 3 and equation (2) by 2, we get,
$6x+9y=6000.........\left( 3 \right)$
$6x+4y=5000.........\left( 4 \right)$
Now subtracting equation (4) from equation (3), we get,
$5y=1000$
$y=200$
Now substituting $y=200$ in equation (3) we get,
$x=700$
Now, we want to find the total cost of 1 table and 5 chairs.
So it becomes, $x+5y=700+5\times 200=1700$.
Therefore we have found out the total cost of 1 table and 5 chairs as $Rs.1700$.
Note: Read the question and see what is asked. Concepts regarding word problems should be clear. A proper assumption should be made. Do not make silly mistakes while substituting. Equate it in a proper manner in order to avoid mistakes.
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