
1.6 gram of an organic compound on combustion gave 4.4 gram carbon dioxide. The \[\% \] of carbon in organic compound is
A) \[\;30\]
B) \[45\]
C) \[60\]
D) \[75\]
Answer
559.5k+ views
Hint: In the given question we have to calculate the percentile of carbon present in the asked compound. The combustion reaction is a chemical reaction that occurs between materials, usually includes oxygen and accompanied by the generation of heat and light in the form of flame.
Complete step by step solution:
combustion is one of the most significant chemical reactions that might be considered a terminating step in the oxidation of various kinds of materials. Though oxidation is considered to be purely the combination of oxygen with any compound, the meaning of the word is expanded to include reaction in which atoms lose electrons, thereby fetching oxidized.
To calculate \[\% \] combustion equations we have to first calculate the molar mass, and also this equation is also used to find empirical formulas. So, it can also be stated as elemental analysis.
Here is how we can calculate the percentage:
Firstly we have to calculate the molar mass of\[C{O_2}\]
The molar mass of \[C{O_2}\] \[ = {\text{ }}\left( {12{\text{ }} + {\text{ }}16{\text{ }} \times 2} \right){\text{ }} = {\text{ }}44\]
We know that the Atomic mass of carbon is \[12\]
so now, we have to calculate weight of carbon in the \[4.4g{\text{ }}C{O_2}\]
\[ = {\text{ }}\dfrac{{12}}{{44}}{\text{ }} \times {\text{ }}4.4\; = \;1.2{\text{ }}grams\] that means the mass of carbon in the compound is \[1.2\] grams
So, to Calculate the % mass of\[\;C\] in the compound of total weight is \[1.6g\]
\[ = {\text{ }}\dfrac{{1.2}}{{1.6}} \times 100\]
\[ = {\text{ }}75{\text{ }}\% \]
Hence, the \[\% \] of carbon in the compound \[ = {\text{ }}75\% \]
Therefore, the correct answer is option D.
Note: The Combustion reaction involves a great variation of spectacles which include wide application in the sciences, industry, the household, and professions, along with the application is mainly based on data and information of chemistry, physics and mechanics.
Complete step by step solution:
combustion is one of the most significant chemical reactions that might be considered a terminating step in the oxidation of various kinds of materials. Though oxidation is considered to be purely the combination of oxygen with any compound, the meaning of the word is expanded to include reaction in which atoms lose electrons, thereby fetching oxidized.
To calculate \[\% \] combustion equations we have to first calculate the molar mass, and also this equation is also used to find empirical formulas. So, it can also be stated as elemental analysis.
Here is how we can calculate the percentage:
Firstly we have to calculate the molar mass of\[C{O_2}\]
The molar mass of \[C{O_2}\] \[ = {\text{ }}\left( {12{\text{ }} + {\text{ }}16{\text{ }} \times 2} \right){\text{ }} = {\text{ }}44\]
We know that the Atomic mass of carbon is \[12\]
so now, we have to calculate weight of carbon in the \[4.4g{\text{ }}C{O_2}\]
\[ = {\text{ }}\dfrac{{12}}{{44}}{\text{ }} \times {\text{ }}4.4\; = \;1.2{\text{ }}grams\] that means the mass of carbon in the compound is \[1.2\] grams
So, to Calculate the % mass of\[\;C\] in the compound of total weight is \[1.6g\]
\[ = {\text{ }}\dfrac{{1.2}}{{1.6}} \times 100\]
\[ = {\text{ }}75{\text{ }}\% \]
Hence, the \[\% \] of carbon in the compound \[ = {\text{ }}75\% \]
Therefore, the correct answer is option D.
Note: The Combustion reaction involves a great variation of spectacles which include wide application in the sciences, industry, the household, and professions, along with the application is mainly based on data and information of chemistry, physics and mechanics.
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