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RS Aggarwal Class 11 Solutions Chapter 27 Limits

Q: 1. Find the Value of the Positive Integer “n” so that limx → 3((xn– 3n)/(x – 3))b = 108.

Given that,limx → 3((xn– 3n)/(x – 3))= 108Now, we have:limx → 3((xn– 3n)/(x-3))= n(3)n-1n(3)n-1 = 108Now, this can be also written as:n(3)n-1 = 4 (27) = 4(3)4-1Therefore, from the rule of exponents, by comparing the exponents in the above equation, we get:n = 4Therefore, the value of the positive integer “n” is 4.

Q: 2. Let f(x) = x2 – 4. Now, Compute limx→2f(x).

If , limx→2f(x) = limx→2x2–4=> 22 – 4 = 4 – 4 = 0Hence the value is zero.

Q: 3. Evaluate limx→2((x2-4)/(x-2)).

It is given that, limx→2((x2-4)/(x-2)) = limx→2((x+2)(x-2)/(x-2))We can cancel the term (x-2) from numerator and denominator. Because the value may not change if the cancellation has happened in both the numerator and the denominator.Then we can get,limx→2 x+2 = 2+2 = 4Hence the value is 4.

Q: 4. Solve limx→2 (sin 2x/x)

Given that,limx→2 (sin 2x/x)We can write it as;limx→2 (sin 2x/2x) × 2By multiplying the two on both sides, we will get,Also, we know that limx→2 (sin x/x)= 1Therefore, limx→2 (sin 2x/2x) × 2 = 1 × 2 = 2Hence the answer is 2.

RS Aggarwal Solutions

RS Aggarwal Class 11 Solutions Chapter 27 Limits

Last updated date: 08th May 2024

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Class 11 RS Aggarwal Chapter 26 Three-Dimensional Geometry Solutions - Free PDF Download

Since it is a bridge between school education and career choice, classes 11th and 12th play a crucial role in students' lives. So every student wants to concentrate on all subjects and strive to get as much knowledge as possible. This also helps them increase their percentage. When coming to RS Aggarwal Solutions Class 11 Limits, the students pay more attention to mathematics and science subjects. Coming to Mathematics, RS Aggarwal Solutions is one of the best books that they want to refer to. The PDF of the RS Aggarwal Class 11 Maths Solutions book provides each chapter in a detailed way with enough practice questions.

Class 11 RS Aggarwal Chapter-27 Limits Solutions - Free PDF Download

RS Aggarwal Solutions provides a theoretical explanation to the Class 11 students for each chapter separately. Now it is about the 27th chapter, which is Limits. It is one of the important mathematics topics that may come again in their higher education of graduation or post-graduation. At this level of Class 11, students are provided with an introduction to the limits. So, it is very important to gain proper knowledge and understand the concept from the basics itself so that the students can easily solve the questions during the Class 11 exam and again understand easily in the further classes.

RS Aggarwal Class 11 Maths Limits Solutions

The limit is a chapter that explains to the students about solving an equation or finding the values from a limit ranging from a minimum value to maximum value; it has several extensions like differentiation, integration, and the summation is denoted by sigma, etc. All these can be introduced to the Class 11th students and are explained step by step. Limits Class 11 Maths RS Aggarwal Solutions ebook, which is available on the official website in a PDF format for free of cost, is perfect for the students to get enough practice. It has plenty of question papers and is prepared by well-experienced experts after thorough verification.

RS Aggarwal Class 11 Solutions Limits provides solutions to each problem of all exercises available in the chapter. The solution is given to the problem, and explanation in a simple and easy method can also be explained in the RS Aggarwal solution PDF. It also provides information about weightage and distribution of marks for every sum to understand how to write step by step in solving a sum and how they may get more marks. The main mortal of every student is to get full marks. This can be achieved by proper preparation and self-assessment.

The students can do a self-assessment with the help of RS Aggarwal Class 11 Maths Limits Solutions. It provides several question papers for practising so that after understanding the chapter, the students need to answer those question papers and assist themselves where they are and also helps to realise their mistakes. It also explains the easiest and simplest method of understanding a problem and solving it.

RS Aggarwal Solutions Class 11 Maths Chapter 27 explains the introduction of limits, the definition of limits, rules, and the formula used in solving the problems. After the explanation of each concept, a few solved examples are given to understand practically. Then the unsolved questions were given to practice. While solving these questions, if students doubt, they can be rectified easily from our Wi-Fi official website through live chat. Otherwise, students have the opportunity to drop their questions in the chatbox and can check the answer later.

RS Aggarwal Maths Class 11 Solutions Limits the notation of limits is Lt. In Lt's base, the range of limits can be expressed so that the students, faculty, or anyone can understand by seeing the problem itself. Some problems in the chapter of limits have a range between 0 to Infinity also. These problems can be expressed with the N rotation and can be solved further where N is the number used to express limits.

Key Takeaways Of Class 11th Students With RS Aggarwal Maths Chapter 27 Limits PDF

Students benefit in many ways from the RS Aggarwal Maths Chapter 27 Solutions from the official website of Vedantu.

It has a simple and understanding language.
Each problem can be explained in a step-by-step manner.
Sufficient examples and exercises were given to the students to get enough practice.
The materials can be prepared by well-experienced faculty after the verification.
Disc PDFs can be available for free of cost, which can be utilized by the students for competitive exams, board exams, and any other entrance tests.

FAQs on RS Aggarwal Class 11 Solutions Chapter 27 Limits

1. Find the Value of the Positive Integer “n” so that limx → 3((xn– 3n)/(x – 3))b = 108.

Given that,

limx → 3((xn– 3n)/(x – 3))= 108

Now, we have:

limx → 3((xn– 3n)/(x-3))= n(3)n-1

n(3)n-1 = 108

Now, this can be also written as:

n(3)n-1 = 4 (27) = 4(3)4-1

Therefore, from the rule of exponents, by comparing the exponents in the above equation, we get:

n = 4

Therefore, the value of the positive integer “n” is 4.

2. Let f(x) = x² – 4. Now, Compute limx→2f(x).

If , limx→2f(x) = limx→2x2–4

=> 22 – 4 = 4 – 4 = 0

Hence the value is zero.

3. Evaluate limx→2((x²-4)/(x-2)).

It is given that,

limx→2((x²-4)/(x-2)) = limx→2((x+2)(x-2)/(x-2))

We can cancel the term (x-2) from numerator and denominator. Because the value may not change if the cancellation has happened in both the numerator and the denominator.

Then we can get,

limx→2 x+2 = 2+2 = 4

Hence the value is 4.

4. Solve limx→2 (sin 2x/x)

Given that,

limx→2 (sin 2x/x)

We can write it as;

limx→2 (sin 2x/2x) × 2

By multiplying the two on both sides, we will get,

Also, we know that limx→2 (sin x/x)= 1

Therefore,

limx→2 (sin 2x/2x) × 2 = 1 × 2 = 2

Hence the answer is 2.

5. Who will be benefited from RS Aggarwal Class 11 Solutions Chapter 27 Limits?

Students who are in class 11th will be definitely benefited from RS Aggarwal Class 11 Solutions Chapter 27 Limits as this deals with one of the most basic chapters of Calculus. Students will get great help in their examinations if they solve each and every question in the exercise and refer to the optimal well-written solution provided by the experts. The Chapter Limits also pave the way for the basics of further chapters. This chapter also appears in JEE examination and other competitive exams.

6. Is RS Aggarwal Class 11 Solutions Chapter 27 Limits an important chapter?

Yes. This chapter helps one to understand the basics of Calculus and thus helps them in further chapters in this book. This is a foundation chapter, hence one of the important chapters in this book. Every student must go through this.