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RD Sharma Class 7 Maths Solutions Chapter 11 - Percentage

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RD Sharma Solutions for Class 7 Maths Chapter 11 - Percentage - Free PDF Download

Students can download the free PDF of RD Sharma Solutions For Class 7 Maths Chapter 11. Our specialist teachers formulate these exercises to help students with exam preparation and to achieve good marks in Maths. The solutions are provided in a stepwise and detailed manner to make learning easy for students. The questions present have been solved by Vedantu’s experts in Maths, and this will help students solve the problems without any difficulties. By practising  RD Sharma solutions sincerely, the students can obtain better results in exams.

Introduction to RD Sharma Class 7 Percentage

RD Sharma Class 7 Chapter 11  Percentage is provided here. This exercise has included verbally based questions based on the topic of a percentage to solve real-life problems. It also covers concepts with an increase or decrease in percentage. In this exercise, students will understand the meaning of per cent and the concept of percentage. This chapter mainly deals with the conversion of a percentage into a fraction and vice versa.

 

Following Are Some of the Important Concepts That Are Being Discussed in This Chapter.

  • Meaning of percent

  • Percent as a fraction

  • Percent as a ratio

  • Conversion of percent into a fraction

  • Conversion of a fraction into percentage

  • Conversion of a ratio into percentage and vice versa

  • Conversion of a percentage into a decimal and vice versa

  • Finding the percentage of a given number

  • Some word problems on percentage


Meaning of percent

Percentage is an approximate value indicating the hundredth parts of any quantity. It means a number or a ratio represented in the form of fractions of 100. It is followed by the percentage sign ‘%’. Percentage can be expressed using abbreviations such as ‘pct’ or ‘pc’. In other words, the percentage is described as how much one quantity comprises another quantity and it is represented in terms of 100.


The percentage is a dimensionless quantity. If we say 80% of a number, then it means 80 per cent of the whole. It can even be expressed in decimal and fraction forms too. One real-life scenario where percentages are used is in our schools to assess our performance through our marks. For example-Manika scored 98% of marks in her exam. So, this percentage is calculated in terms of total marks obtained by Manika in all the subjects to the total maximum marks and then the result will be multiplied by 100. 


Percent as a fraction

We can express percentages in terms of fractions too. For example, if we represent 8% in the form of a fraction, it will be 8 parts of 100 or \[\frac{8}{100}\]. 


Percent as a ratio

Percentages like fractions can be expressed in terms of ratios too. It’s very easy to do so. We first write the percentage in the form of x:y. Where x is the given percentage and y is 100.


Conversion of percent into a fraction

In order to convert percent into a fraction, we need to put the values in the given formula.


Percent to fraction formula:

\[ Fraction =\frac{(Given Percentage)}{100}\]

Let’s understand this better with the help of an illustration:


Represent 25% in terms of a fraction.

Here, 20% can be represented as \[\frac{25}{100}\] which is then simplified to get the desired fraction.

\[\frac{25}{100}=\frac{1}{4}\]

Thus the fraction comes out to be \[\frac{1}{4}\].


Conversion of a fraction into a percentage

We can convert a fraction into a percentage too. In order to convert percent into a fraction, we need to put the values in the given formula.

\[Percentage = Fraction\times  100=(\frac{1}{4})\times  100=25\]%

Thus the answer is 25%.


Conversion of a percent to ratio and vice versa

Per cent can easily be converted into a ratio and vice versa by the following steps.


Percent to ratio formula:

Ratio= Given percentage: 100

Let’s understand this better with the help of an illustration. 


Convert 25 per cent to a ratio. 

To do so, we put 25 in the place of x and 100 in the place of y in the x:y format. 

25:100

On simplifying, we get-

1:4

In order to convert the ratio to percent, we first need to convert the ratio to a fraction and follow the steps of conversion of a fraction to a percentage.


Ratio to percent formula:

Ratio = x:y

\[Fraction =\frac{x}{y}\]

\[Percent = \frac{x}{y}\times100\]

Let’s understand this better with the help of an illustration.


Convert 1:4 to a percentage.

Here, we convert 1:4 to a fraction, \[\frac{1}{4}\]

Then we multiply 100 to the fraction.

\[(\frac{1}{4})\times\] 100=25%


Conversion of a percentage into a decimal and vice versa

We can convert a percentage into a decimal and vice versa by following the given steps. Let us see how to convert percent to decimal.


Percent to decimal formula:

Decimal=\[\frac{Percent}{100}\]

Let us understand this better with the help of an illustration.


Convert 17% to decimal.

In order to do this we simply divide 17 by 100

\[\Rightarrow\left ( \frac{17}{100} \right )\] = 0.17

Hence, it has been converted to decimal form.


Decimal to percent formula:

Percent = Decimal \[\times\] 100

Let us understand this better with the help of an illustration.


Convert 0.17 to percentage.

Here, we simply have to multiply 100 to the given number.

0.17\[ \times\] 100= 17%

Thus, it comes out to be 17 per cent.


Finding the percentage of a given number

Finding the percentage of a number is very easy. We just have to divide the given number by the total and multiply 100 to it. 


Percentage formula:

\[Percentage=\left ( \frac{Given Number}{Total } \right )\times 100\]

This can be illustrated further with the help of an example.

Suppose we have to find 20% of 21. 

The percentage will be,

Percentage = \[\frac{20}{21}\times100\]

95.238%


Some word problems on percentage

Q.After subtracting a commission of 5%, a moped costs Rs 15200. What is its gross value?

Solution:

Let us suppose that the gross value of the moped is Rs x.

Commission on the moped = 5%

x-5% of x=x-\[\left ( \frac{5x}{100} \right )\]=\[\frac{(100x-5x)}{100}\]=\[\frac{95x}{100}\]

Now, price of the moped after reducing the commission = Rs 15200

Then \[\frac{95x}{100}\]=15200

So, x= Rs \[\frac{(15200\times 100)}{95}\] = Rs (160 \[\times \] 100= Rs 16000

Therefore, the gross value of the moped is Rs 16000.

Q.Michael had a science exam and got 30 correct and 10 incorrect answers. What is the percentage of correct answers?

Solution:

Total number of answers = 30+10= 40

Percentage of correct answers = \[ \frac{30}{40}\times 100\]

=\[\frac{3000}{40}\]

= 75

Therefore, he got 75% of correct answers.


Exercises in RD Sharma Solutions For Class 7 Maths Chapter 11

 

Conclusion

For students who wish to score high marks in Maths, RD Sharma Solutions is the best study material. The subject matter experts at Vedantu have prepared the  RD Sharma solutions to help the students who are finding difficulties in solving them. Students can easily access answers to the problems present in RD Sharma Class 7 Chapter 11  by downloading the PDF. It contains all solutions in a detailed manner and also expects questions to be asked in the exam. After solving these problems students will get more confident about the exam.

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FAQs on RD Sharma Class 7 Maths Solutions Chapter 11 - Percentage

1. How do the RD Sharma Class 7 solutions explain the method for converting a fraction to a percentage?

The RD Sharma solutions for Class 7 Maths provide a clear, step-by-step method for this conversion. To convert any fraction to a percentage, you simply need to multiply the given fraction by 100 and then place the percent symbol (%) after the result. For example, to convert 3/4 to a percentage, the calculation shown would be (3/4) × 100 = 75%.

2. What are the key application-based percentage problems covered in the RD Sharma Class 7 Chapter 11 solutions?

The solutions for RD Sharma Class 7 Chapter 11 cover a wide range of real-world applications of percentages, helping students understand its practical use. Key problem types include:

  • Calculating profit and loss percent in transactions.

  • Finding the Simple Interest (SI) on a given principal amount.

  • Determining the percentage increase or decrease in a quantity.

  • Solving problems involving mixtures, discounts, and commissions.

3. How do the RD Sharma solutions for Chapter 11 help in solving complex percentage problems not found in the NCERT textbook?

RD Sharma solutions are designed to build a deeper understanding beyond the standard textbook. They help by providing a larger variety of questions, including Higher Order Thinking Skills (HOTS) problems. These solutions demonstrate how to break down complex, multi-step word problems into simpler parts, apply the correct formula, and build a strong foundation for more advanced topics in higher classes.

4. Why is it important to convert quantities to the same unit before calculating a percentage, as demonstrated in the RD Sharma solutions?

It is crucial because a percentage is a ratio that compares two like quantities. If the units are different (e.g., comparing grams to kilograms or paise to rupees), the comparison becomes mathematically incorrect and meaningless. The RD Sharma solutions consistently show the step of converting all values to a common base unit first to ensure the calculation is accurate and the resulting percentage is valid.

5. What is the step-by-step method to calculate profit percent as explained in the solutions for RD Sharma Chapter 11?

The solutions in RD Sharma Chapter 11 break down the calculation of profit percent into logical steps:

  • First, determine the Cost Price (CP) and the Selling Price (SP).

  • Next, calculate the profit by subtracting the Cost Price from the Selling Price (Profit = SP - CP).

  • Finally, apply the profit percent formula: Profit % = (Profit / Cost Price) × 100. The solutions show this calculation clearly for various scenarios.

6. What is the main difference between calculating a percentage increase and a percentage decrease, and how do the RD Sharma solutions illustrate this?

The main difference lies in the calculation of the change. For a percentage increase, you find the amount of increase and divide it by the original, smaller amount. For a percentage decrease, you find the amount of decrease and divide it by the original, larger amount. The RD Sharma solutions illustrate this by solving different problems for each case, always emphasising that the 'original value' is the denominator in the formula, which is a common point of confusion for students.

7. How can I use the RD Sharma solutions to find the original amount if only a percentage of it is known?

The RD Sharma solutions provide a systematic algebraic method for this type of problem. The general approach is to:

  • Assume the unknown original amount is 'x'.

  • Set up an equation based on the given information (e.g., 20% of x = 50, which is 0.20 * x = 50).

  • Solve the linear equation for 'x' to find the original value. The solutions provide detailed, solved examples of this method.

8. Beyond just getting answers, what problem-solving strategies can be learned from the detailed RD Sharma Class 7 solutions for Percentage?

Studying these solutions teaches valuable problem-solving strategies. Students learn to systematically decode word problems by identifying the 'base' value, the 'part', and the 'rate'. They also learn the importance of structuring their answers, showing each step of the calculation clearly, and double-checking their work—skills that are essential for performing well in exams and for understanding more complex mathematical concepts later on.