Question

Ziegler-Natta catalyst is used to prepare:
A.) Low-density polythene
B.) Teflon
C.) High density polythene
D.) Nylon$ - 6$

Answer 1

Hint: Ziegler-Natta is a catalyst which is a mixture of Triethylaluminum(${({C_2}{H_5})_3}Al$) and Titanium tetrachloride ($TiC{l_4}$) . It is basically used to prepare high density polythene or plastics.

Complete step by step answer:
As we know that catalyst is a substance that increases or decreases the rate of reaction without taking part in a reaction. Ziegler-Natta catalyst is named after the name of two chemists- Karl Ziegler and Giulio Natta. This catalyst is a solution of two substances, one is Triethylaluminum(${({C_2}{H_5})_3}Al$) and second is Titanium tetrachloride($TiC{l_4}$). Thus, we can say that Ziegler-Natta has the following formula: $TiC{l_4} - Al{(C{H_3})_2}{(C{H_2})_2}Cl$. Ziegler-Natta catalyst also increases the rate of polymerization. It is used for polymerization of alkenes to produce polymers. Ziegler-Natta catalyst polymerization is a versatile reaction for producing polymers.
The most important application of Ziegler -Natta is that it is used for the production of high density polyethene or plastics. High density polyethene is a polymer which is made by polymerization of ethylene. It is a thermoplastic polymer whose shapes can be changed by application of heat and pressure. The preparation of high density polymer can be shown as :
$nC{H_2} = C{H_2}\xrightarrow{{Ziegler - Natta{\text{ }}Catalyst}}{[ - C{H_2} - C{H_2} - ]_n}$
Hence, C is the correct option.


Note:
 The Ziegler-Natta catalyst has a limitation that it does not work for some monomers . We cannot generate products like poly - vinyl chloride and acrylates by Ziegler-Natta polymerization.