You are given two converging lenses of focal length \[1.25cm\] and $5cm$ to design a compound microscope. If it is desired to have a magnification of $30$, find out the separation between the objective and the eyepiece.
Answer
603.6k+ views
Hint: An upright microscope that uses two lens sets (a compound lens system) to achieve a higher magnification than a stereomicroscope is a compound microscope. A compound microscope produces a two-dimensional view, while a three-dimensional view is given by a stereo microscope. Tiny samples not identifiable with the naked eye are seen with the compound microscopes. Usually these samples are mounted under the microscope on a slide.
Magnification of a compound microscope can be written as,
$M = {M_0} {M_e} $
Where the magnification of microscope is $M$, ${M_0} $ is the magnification due to objective and ${M_e} $ is magnifying power by the eye piece
Complete step by step solution:
Magnification of a compound microscope is given by:
$M = {M_0} {M_e} $
Where the magnification of microscope is $M$, ${M_0} $ is the magnification due to objective and ${M_e} $ is magnifying power by the eye piece
We know that,
${M_0} = \dfrac{L}{{{f_0}}}$ and ${M_e} = \dfrac{{25}}{{{f_e}}}$
Where $L$ is the distance between objective and eyepiece, ${f_0} $ is the focal length of the objective and ${f_e} $ is the focal length of the eye piece.
Therefore, $M = \dfrac{L}{{{f_0}}} \times \dfrac{{25}}{{{f_e}}}$
It is given that, ${f_0} = 1.25cm$, ${f_e} = 5cm$ and $M = 30$
We get,
$\Rightarrow 30 = \dfrac{L}{{1.25}} \times \dfrac{{25}}{5}$
$\Rightarrow L = 7.5cm$
Therefore, the distance between the objective and eyepiece is $7.5cm$.
Note: With the aid of a compound microscope, two lenses can transcend the limits on resolution (and thus magnification power) imposed by the restrictions of the simple microscope. One of them has a small focal length and is positioned near the object under investigation. It is used to create a real picture in the middle of the front, eye or eye lens. The oculus forms a broader virtual image that the viewer can see. The compound microscope magnification strength is the combination of the lens magnification and the eyepiece magnification.
Magnification of a compound microscope can be written as,
$M = {M_0} {M_e} $
Where the magnification of microscope is $M$, ${M_0} $ is the magnification due to objective and ${M_e} $ is magnifying power by the eye piece
Complete step by step solution:
Magnification of a compound microscope is given by:
$M = {M_0} {M_e} $
Where the magnification of microscope is $M$, ${M_0} $ is the magnification due to objective and ${M_e} $ is magnifying power by the eye piece
We know that,
${M_0} = \dfrac{L}{{{f_0}}}$ and ${M_e} = \dfrac{{25}}{{{f_e}}}$
Where $L$ is the distance between objective and eyepiece, ${f_0} $ is the focal length of the objective and ${f_e} $ is the focal length of the eye piece.
Therefore, $M = \dfrac{L}{{{f_0}}} \times \dfrac{{25}}{{{f_e}}}$
It is given that, ${f_0} = 1.25cm$, ${f_e} = 5cm$ and $M = 30$
We get,
$\Rightarrow 30 = \dfrac{L}{{1.25}} \times \dfrac{{25}}{5}$
$\Rightarrow L = 7.5cm$
Therefore, the distance between the objective and eyepiece is $7.5cm$.
Note: With the aid of a compound microscope, two lenses can transcend the limits on resolution (and thus magnification power) imposed by the restrictions of the simple microscope. One of them has a small focal length and is positioned near the object under investigation. It is used to create a real picture in the middle of the front, eye or eye lens. The oculus forms a broader virtual image that the viewer can see. The compound microscope magnification strength is the combination of the lens magnification and the eyepiece magnification.
Recently Updated Pages
Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Biology: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Class 12 Question and Answer - Your Ultimate Solutions Guide

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Trending doubts
Which is more stable and why class 12 chemistry CBSE

Which are the Top 10 Largest Countries of the World?

Draw a labelled sketch of the human eye class 12 physics CBSE

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE

What are the major means of transport Explain each class 12 social science CBSE

Sulphuric acid is known as the king of acids State class 12 chemistry CBSE

