Question

$Xe{F}_4$ on partial hydrolysis produces ________.
A. $Xe{F}_4$
B. $Xe{F}_5$
C. $XeO{F}_2$
D. $Xe{O}_3$

Answer 1

Hint:In order to the question, first we will react $Xe{F}_4$ by adding $H_{2}O$ . In partial hydrolysis, the amount of water is limited. Hydrolysis is the process of adding water to a molecule for the purpose of breaking it into simpler compounds.

Complete step-by-step answer:$Xe{F}_4$ on partial hydrolysis produces Xenon Oxyfluorides $XeO{F}_2$ . This reaction can be symbolically given as:
$Xe{F}_4+H_{2}O\to XeO{F}_2+2HF$
In the above reaction, $Xe{F}_4$ is added with the limited amount of water or $H_{2}O$ and gives the product as Xenon Oxydifluoride and Hydrogen Fluoride. This reaction is known as the partial reaction of $Xe{F}_4$ .Hydrolysis of other xenon fluorides ($Xe{F}_2$ and $Xe{F}_4$ ) apparently does result in some redox reactions, with some oxygen being oxidized and some xenon being reduced.

Hence, the correct option is (C.) $XeO{F}_2$ .

Note:The oxyfluorides of xenon namely xenon oxydifluoride, $XeO{F}_2$ and xenon oxytetrafluoride, $$$XeO{F}_4$ are also obtained by the partial hydrolysis of $Xe{F}_4$ and $Xe{F}_6$ respectively. The structure of xenon compounds can be explained on the basis of the VSEPR theory as well as the concept of hybridization.