Question

Write the favorable factors for the formation of ionic bonds?

Answer 1

Hint: Try to recall that ionic bonds are formed by complete transfer of electrons from one atom to another so as to complete their octet and hence acquire the stable nearest noble gas electronic configuration. Now by using this you can easily answer the given question.

Complete step by step solution:
It is known to you that the bond formed between a metal and non-metal which involves complete transfer of electrons from metal to nonmetal atom to form oppositely charged ions is called ionic bond.
The conditions favorable for the formation of ionic bond are as follows:
One of the atoms must be a metal and the other must be a non-metal.
The metal atom should have very low ionization energy so that it can lose electrons easily to form cations (positively charged ions) i.e. metal atoms must be highly electropositive.
The non-metal should have a very high electron affinity, so that it can easily attract electrons (from the metal) and form anions (negatively charged ions) i.e. non-metal atoms must be highly electronegative.

Note: It should be remembered to you that the two atoms involved in forming ionic bonds must be positioned very far away in the periodic table. The metal atom must be on the very left side and the non-metal must be on the very side of the periodic table.
Also, the energy released when the requisite number of gaseous positive and negative ions combines to form one mole of the ionic compound is called lattice enthalpy.