Question

Write the E – Z configuration of the following compound .

Answer 1

Hint: When the two priority groups are on the same side then the configuration is said to be in Z configuration. While if these two priority groups are on different sides then it is called E configuration. These E and Z configurations are applicable on double bonds only.

Complete answer:
The E-Z configuration is named after analyzing the two groups at each end of a double bond. The groups are lower priority and higher priority groups . The priority of a group is decided by the CIP rules. The first rule is that the atom having higher atomic number will receive the higher priority .This rule is enough to give the answer to our question. Firstly, according to the IUPAC number, it is organic.

Now according to the CIP rule ,first find a double bond . It is present at $1$ and $3$ positions . Now we have to give priority to groups surrounded by double bonds at these positions.

For position $1$ -
At the right side of the double bond we have $Cl$ and $H$ . Since the atomic number of Chlorine $\left( {17} \right)$ is higher than that of hydrogen $\left( 1 \right)$ .Therefore $Cl$ receives higher priority than $H$ . Similarly at the left side we have Carbon atom and Hydrogen. Again due to higher atomic number the carbon atom is at higher priority . Now compare the positions of the groups .We can easily see that higher priority groups at both sides of the double side are at the same side i.e upper side. Hence we can say it is in Z configuration.
Similarly we can give priorities at position $3$ $C$ too. $Br$ and $C$ are higher priorities located on opposite sides. Therefore it is E configuration. Thus it is $1Z{\text{ , 3E}}$ .

Note:
E-Z nomenclature is introduced in place of cis trans . When the cis trans does not work then we have to apply E-Z nomenclature. There are other rules for CIP. We use only one basic rule but there is a complete list of rules for determining the priority of groups.