Question

Write down three consecutive predecessors of 7510001.

Answer 1

Hint: Here, we are given a whole number. So its predecessor can be obtained by subtracting 1 from the given number. Similarly, we subtract 1 from the result obtained to get the second predecessor, and then subtract 1 again to get the third predecessor from the result obtained later.

Complete step-by-step answer:
 The terms successor and predecessor of a number are the terms that are exactly after or before a particular number, respectively. Simply, Successor and predecessor of a number are called as after a particular number and before a particular number respectively.
The first consecutive predecessor is 7510001 – 1 = 7510000
The second consecutive predecessor = predecessor of 7510000 = 7510000 – 1 = 7509999
The third consecutive predecessor = predecessor of 7509999 = 7509999 – 1 = 7509998
So, three consecutive predecessors of 7510001 is 7510000, 7509999 and 7509998.

Note: Predecessor refers to the previous term of a particular term while the successor refers to the next term of a particular term. If we wish to find a successor a whole number, then we must add one to the particular given number. And if we wish to find the predecessor of a particular number, then we must subtract one from the given number.
Alternatively, first predecessor of 7510001 = 7510001 – 1 = 7510000
Second predecessor of 7510001 = 7510001 – 2 = 7509999
Third predecessor of 7510001 = 7510001 – 3 = 7509998
Similarly we can get as many predecessors of 7510001 and we wish by continuing the same process.