Write down the names of compounds represented by the following formulae:
$\left( i \right){\text{ }}A{l_2}{\left( {S{O_4}} \right)_3}$
$\left( {ii} \right){\text{ }}CaC{l_2}\;$
$\left( {iii} \right){\text{ }}{K_2}S{O_4}\;$
$\;\left( {iv} \right){\text{ }}KN{O_3}\;$
$\;\left( v \right){\text{ }}CaC{O_3}$
Answer
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Hint: The naming of chemical compounds is done on the basis of some principles which are given by IUPAC which is the International Union of Pure and Applied Chemistry. So, we need to follow these rules strictly and deduce the chemical name of the compounds by their chemical formulas which are given above.
Complete answer:
In order to deduce the name of the chemical compound, we first need to know the rule given by IUPAC (International Union of Pure and Applied Chemistry) to name a chemical compound.
According to which the name cationic part of compound is written before the anionic part.
$\left( i \right){\text{ }}A{l_2}{\left( {S{O_4}} \right)_3}$
In the above given compound, aluminium ion $(A{l^{3 + }})$ and sulphate ion $(SO_4^{2 - })$ are present. Hence, we can name this compound as Aluminium Sulphate.
$\left( {ii} \right){\text{ }}CaC{l_2}\;$
In the above given compound, calcium ion $(C{a^{2 + }})$ and chloride ion $(C{l^ - })$ are present. Hence, we can name this compound as Calcium Chloride.
$\left( {iii} \right){\text{ }}{K_2}S{O_4}\;$
In the above given compound, potassium ion $({K^ + })$ and sulphate ion $(SO_4^{2 - })$ are present. Hence, we can name this compound as Potassium Sulphate.
$\;\left( {iv} \right){\text{ }}KN{O_3}\;$
In the above given compound, potassium ion $({K^ + })$ and nitrate ion $(NO_3^ - )$ are present. Hence, we can name this compound as Potassium Nitrate.
$\;\left( v \right){\text{ }}CaC{O_3}$
In the above given compound, calcium ion $(C{a^{2 + }})$ and carbonate ion $(CO_3^{2 - })$ are present. Hence, we can name this compound as Calcium Carbonate.
Hence, we can say that diborane is a strong electrophile.
Note:
There are two types of naming methods, one is according to the IUPAC nomenclature (formal name) and the naming method is giving the common names (informal names). For example, if we take the example of $NaOH$ , its chemical name is Sodium hydroxide while its common name is caustic soda.
Complete answer:
In order to deduce the name of the chemical compound, we first need to know the rule given by IUPAC (International Union of Pure and Applied Chemistry) to name a chemical compound.
According to which the name cationic part of compound is written before the anionic part.
$\left( i \right){\text{ }}A{l_2}{\left( {S{O_4}} \right)_3}$
In the above given compound, aluminium ion $(A{l^{3 + }})$ and sulphate ion $(SO_4^{2 - })$ are present. Hence, we can name this compound as Aluminium Sulphate.
$\left( {ii} \right){\text{ }}CaC{l_2}\;$
In the above given compound, calcium ion $(C{a^{2 + }})$ and chloride ion $(C{l^ - })$ are present. Hence, we can name this compound as Calcium Chloride.
$\left( {iii} \right){\text{ }}{K_2}S{O_4}\;$
In the above given compound, potassium ion $({K^ + })$ and sulphate ion $(SO_4^{2 - })$ are present. Hence, we can name this compound as Potassium Sulphate.
$\;\left( {iv} \right){\text{ }}KN{O_3}\;$
In the above given compound, potassium ion $({K^ + })$ and nitrate ion $(NO_3^ - )$ are present. Hence, we can name this compound as Potassium Nitrate.
$\;\left( v \right){\text{ }}CaC{O_3}$
In the above given compound, calcium ion $(C{a^{2 + }})$ and carbonate ion $(CO_3^{2 - })$ are present. Hence, we can name this compound as Calcium Carbonate.
Hence, we can say that diborane is a strong electrophile.
Note:
There are two types of naming methods, one is according to the IUPAC nomenclature (formal name) and the naming method is giving the common names (informal names). For example, if we take the example of $NaOH$ , its chemical name is Sodium hydroxide while its common name is caustic soda.
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